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babymother [125]
3 years ago
12

There is a number line below and an equation. How do you solve the equation and then put it on the number line?

Mathematics
1 answer:
jasenka [17]3 years ago
7 0
Im sure youve figured it out by now

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4.9t^2-2.78t-1.15=0 what is the value of T
zzz [600]

Answer:

t = 139/490 + sqrt(75671)/490 or t = 139/490 - sqrt(75671)/490

Step-by-step explanation:

Solve for t:

4.9 t^2 - 2.78 t - 1.15 = 0

4.9 t^2 - 2.78 t - 1.15 = (49 t^2)/10 - (139 t)/50 - 23/20:

(49 t^2)/10 - (139 t)/50 - 23/20 = 0

Multiply both sides by 10/49:

t^2 - (139 t)/245 - 23/98 = 0

Add 23/98 to both sides:

t^2 - (139 t)/245 = 23/98

Add 19321/240100 to both sides:

t^2 - (139 t)/245 + 19321/240100 = 75671/240100

Write the left hand side as a square:

(t - 139/490)^2 = 75671/240100

Take the square root of both sides:

t - 139/490 = sqrt(75671)/490 or t - 139/490 = -sqrt(75671)/490

Add 139/490 to both sides:

t = 139/490 + sqrt(75671)/490 or t - 139/490 = -sqrt(75671)/490

Add 139/490 to both sides:

Answer: t = 139/490 + sqrt(75671)/490 or t = 139/490 - sqrt(75671)/490

3 0
2 years ago
A cube+a square b+ ab square<br><br><br> Please help
Advocard [28]

Step-by-step explanation:

{a}^{3}  +  {a}^{2} b + a {b}^{2}

[Taking a common from each term]

= a( {a}^{2}  + ab +  {b}^{2} )

as \:  {a}^{2}  + ab +  {b}^{2}  =  {(a + b)}^{2}

Hence,

= a {(a + b)}^{2} (ans)

8 0
3 years ago
Asap plz thankyouuuuuuuuuuuuuuuuuuuuuuuu
maria [59]
Number 5 is 135 because angle 3 is congruent to 7 and 7 is 135
5 0
3 years ago
What is the slope of the line that passes through the given points? (1 point)
frez [133]
(1/2,3)(2,3/4)
slope = (3/4 - 3) / (2 - 1/2) = (3/4 - 12/4) / (4/2 - 1/2) =
(-9/4) / (3/2) = -9/4 * 2/3 = -18/12 = -3/2
4 0
3 years ago
What is 4/5 decomposed
NeTakaya
It is either 0.80 or 80% I believe
7 0
3 years ago
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