If i have ten fish and six drawn and two come with the left of the fish that didn't drawn but one dies how many fish do i have ?
2 answers:
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Answer:
<u> x = 16</u>
Step-by-step explanation:
See the attched figure
We should know that, one of the properties of the rhombus is the diagonals bisect the angles of the rhombus.
Given:
m∠ABC = 84 and m∠ABE = 3x − 6
So, m∠ABE = 0.5 * m∠ABC = 0.5 * 84 = 42
∴ 3x - 6 = 42
Solve for x
3x = 42 + 6 = 48
x = 48/3 = 16
<u>∴ x = 16</u>
