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Vaselesa [24]
3 years ago
10

What is the value of x from the angles

Mathematics
1 answer:
DIA [1.3K]3 years ago
7 0

Answer:

ans: 23°

Step-by-step explanation:

(5y + 6)° = 121°

being alternate exterior angle

y°= (121 - 6)/5 = 23°

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Gloria rides a bike 8 miles in 40 minutes.Nanette rides a bike 5 miles in 30 minutes.Who biked the farthest.
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Gloria biked the farthest.
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If you put a sugar cube in hot tea does it dissolve or melt and why?
iren2701 [21]
The molecules in the sugar dissolved in water. it did not dissociate though, just dissolved. the atoms in each individual molecule stayed in tact, but the intermolecular forces broke apart.
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There are 8 roses in a vase of 13 flowers. The rest are daisies.
Blizzard [7]

Answer:

  1. 5:13
  2. 8:5

Step-by-step explanation:

For first part:

  1. Roses = 8
  2. Daises = All flowers - Roses
  3. Daises = 13 - 8
  4. Daises = 5
  5. Daises:All Flowers = 5:13

For second part:

  1. Roses:Daises = 8:5

I hope this helps!

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2 years ago
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Which expression is equivalent to 8(2a)?<br> 8(2 + a)<br> 8 + 2a<br> 8(a + a)<br> a + 10
Nadusha1986 [10]

Answer:

8(2+a) is the answer that you need there really is not much thought to it

4 0
2 years ago
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A manufacturer of chocolate candies uses machines to package candies as they move along a filling line. Although the packages ar
Elenna [48]

Answer:

We conclude that the mean amount packaged is equal to 8.17 ounces.

Step-by-step explanation:

We are given that in a particular sample of 50 packages, the mean amount dispensed is 8.171 ​ounces, with a sample standard deviation of 0.052 ounces.

Let \mu = <u><em>population mean amount packaged. </em></u>

So, Null Hypothesis, H_0 : \mu = 8.17 ounces    {means that the mean amount packaged is equal to 8.17 ounces}

Alternate Hypothesis, H_A : \mu\neq 8.17 ounces    {means that the mean amount packaged is different from 8.17 ounces}

The test statistics that will be used here is <u>One-sample t-test statistics</u> because we don't know about the population standard deviation;

                               T.S.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~  t_n_-_1

where, \bar X = sample mean amount dispensed = 8.171 ounces

             s = sample standard deviation = 0.052 ounces

            n = sample of packages = 50

So, <u><em>the test statistics</em></u> =  \frac{8.171-8.17}{\frac{0.052}{\sqrt{50} } }  ~   t_4_9

                                    =  0.1359  

The value of t-test statistics is 0.1359.

<u>Also, the P-value of test-statistics is given by;</u>

the meaning of the​ p-value is that the p-value is the probability of obtaining a sample mean that is equal to or more extreme than 0.001 ounces away from8.17 if the null hypothesis is true.

                    P-value = P( t_4_9 > 0.136) = More than 40% {from the t-table}

Since the P-value of our test statistics is more than the level of significance of 0.01, so <u><em>we have insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that the mean amount packaged is equal to 8.17 ounces.

6 0
3 years ago
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