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2 years ago

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The number of students attending the fall play was 150 fewer then 3 times the number of adults. Together, students and adults pu

rchased 1778 tickets.How many students attended the fall play?

1 answer:

hodyreva [135]2 years ago

4 0

Answer:

Number of students attended the fall play $=1296$

Step-by-step explanation:

Let number of adults $=x$

Number of students $=3\times number\ of\ adults-150=3x-150$

Given that total number of tickets $=1778$

Number of students+ Number of adults $=1778$

$x+(3x-150)=1778\\4x-150=1778\\4x=1778+150\\4x=1928\\x=\frac{1928}{4}\\x=482$

Number of adults $=482$

Number of students $=3x-150=3\times482-150=1446-150=1296$

Number of students $=1296$

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Four plumbers estimated the length of the radius of a cylindrical pipe. The estimates made by

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Answer:

B. $\frac{\sqrt{3}}{11}, \frac{\pi}{24}, \frac{3}{25}, \frac{9}{100}$

Step-by-step explanation:

The question is not properly presented. See attachment for proper presentation of question

From the attachment, we have that:

$W = \frac{3}{25}$

$X = \frac{\sqrt{3}}{11}$

$Y = \frac{9}{100}$

$Z = \frac{\pi}{24}$

Required

Order from greatest to least

First, we need to simplify each of the given expression (in decimals)

$W = \frac{3}{25}$

$W = 0.12$

$X = \frac{\sqrt{3}}{11}$

Take square root of 3

$X = \frac{1.73205080757}{11}$

$X = 0.15745916432$

$X = 0.16$ --- approximated

$Y = \frac{9}{100}$

$Y = 0.09$

$Z = \frac{\pi}{24}$

Take π as 3.14

$Z = \frac{3.14}{24}$

$Z = 0.13083333333$

$Z = 0.13$ --- approximated

List out the results, we have:

$W = 0.12$ $X = 0.16$ $Y = 0.09$ $Z = 0.13$

Order from greatest to least, we have:

$X = 0.16$ $Z = 0.13$ $W = 0.12$ $Y = 0.09$

Hence, the order of arrangement is:

$X = \frac{\sqrt{3}}{11}$ $Z = \frac{\pi}{24}$ $W = \frac{3}{25}$ $Y = \frac{9}{100}$

i.e.

$\frac{\sqrt{3}}{11}, \frac{\pi}{24}, \frac{3}{25}, \frac{9}{100}$

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A document that is 35 in. By 40 in. Is redrawn at 1 1/2 scale and then redrawn at 1/4 scale. What are the final dimensions of th

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2 years ago

Calculate the Laplace transforms of the following from the definition. 1. y = t^2. y = t^3

Likurg_2 [28]

Answer:

1) $L(y)=\frac{2}{s^{3}}$

2) $L(y)=\frac{6}{s^{4}}$

Step-by-step explanation:

To find : Calculate the Laplace transforms of the following from the definition ?

Solution :

We know that,

Laplace transforms of $t^n$ is given by,

$L(t^n)=\frac{n!}{s^{n+1}}$

1) $y=t^2$

Laplace of y,

$L(y)=L(t^2)$ here n=2

$L(y)=\frac{2!}{s^{2+1}}$

$L(y)=\frac{2}{s^{3}}$

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Laplace of y,

$L(y)=L(t^3)$ here n=3

$L(y)=\frac{3!}{s^{3+1}}$

$L(y)=\frac{3\times 2}{s^{4}}$

$L(y)=\frac{6}{s^{4}}$

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2 years ago