Part A. You have the correct first and second derivative.
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Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.
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Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out
To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0.
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well.
Answer:
x = -2 + 2 i or x = -2 - 2 i
Step-by-step explanation:
Solve for x:
x^2 + 4 x + 8 = 0
Subtract 8 from both sides:
x^2 + 4 x = -8
Add 4 to both sides:
x^2 + 4 x + 4 = -4
Write the left hand side as a square:
(x + 2)^2 = -4
Take the square root of both sides:
x + 2 = 2 i or x + 2 = -2 i
Subtract 2 from both sides:
x = -2 + 2 i or x + 2 = -2 i
Subtract 2 from both sides:
Answer: x = -2 + 2 i or x = -2 - 2 i
Unfortunately, Nicholas' steps in simplifying the fraction is not reflected in the question. However, the general idea of the simplifying fraction is to find the greatest common factor (GCF) of both the numerator and the denominator. In this case, the GCF is 10. Then, divide both numbers by the GCF. The answer for this item should be 2/3.
Answer:
Step-by-step explanation:
