Answer:
10w^2 + 24w + 13
Step-by-step explanation:
use Foil method
0.10d + 0.25q = 3.55
q = d + 3
0.10d + 0.25(d + 3) = 3.55
0.10d + 0.25d + 0.75 = 3.55
0.10d + 0.25d = 3.55 - 0.75
0.35d = 2.80
d = 2.80/0.35
d = 8.....8 dimes
q = d + 3
q = 8 + 3
q = 11 <=== 11 quarters
Answer:
y=60° b=60°
Step-by-step explanation:
the sum of all degrees of interior triangle is 180
in the first one, 30° and 90° have been given.(that small square represent 90°)
so 180°-90°-30°=60°
in the second one, the 120° is on the other side of a line, a line has a degree of 180, therefore the interior angle is 60°, the same rule 180°-2*60°=60°
#1
- The limit tends to 0
- Hence c=0
- Here limit tends to 1
- Hence c=1
- Here x tends to infty.
- c=infty
For the fourth one limit also tends to zero
Imx->0 (asin2x + b log(cosx))/x4 = 1/2 [0/0 form] ,applying L'Hospital rule ,we get
= > limx->0 (2a*sinx*cosx - (b /cosx)*sinx)/ 4x3 = 1/2 => limx->0 (a*sin2x - b*tanx)/ 4x3 = 1/2 [0/0 form],
applying L'Hospital rule again ,we get,
= > limx->0 (2a*cos2x - b*sec2x) / 12x2 = 1/2
For above limit to exist,Numerator must be zero so that we get [0/0 form] & we can further proceed.
Hence 2a - b =0 => 2a = b ------(A)
limx->0 (b*cos2x - b*sec2x) / 12x2 = 1/2 [0/0 form], applying L'Hospital rule again ,we get,
= > limx->0 b*(-2sin2x - 2secx*secx.tanx) / 24x = 1/2 => limx->0 2b*[-sin2x - (1+tan2x)tanx] / 24x = 1/2
[0/0 form], applying L'Hospital rule again ,we get,
limx->0 2b*[-2cos2x - (sec2x+3tan2x*sec2x)] / 24 = 1/2 = > 2b[-2 -1] / 24 = 1/2 => -6b/24 = 1/2 => b = -2
from (A), we have , 2a = b => 2a = -2 => a = -1
Hence a =-1 & b = -2
