X = 6 cos(t)
y = 3 sin(t)
we can rewrite these equations as:
Taking squares of both equations we get:
Adding both the equations, we get:
Answer: 20.71
Step-by-step explanation:
Answer: 1766.3
Step-by-step explanation:
Answer:
455.
Step-by-step explanation:
Yes. You require the number of combinations of 3 from 15.
15C3
The formula for this is 15! / 12! 3! or you can do itr as follows
15C3 = 15*14*13/3*2*1
= 5*7*13
= 35*13
= 455.
Answer:the number of advance tickets sold is 35
the number of same day tickets sold is 40
Step-by-step explanation:
Let x represent the number of advance tickets sold.
Let y represent the number of same day tickets sold.
For one performance, there were 75 tickets sold in all. This means that
x + y = 75
Advance tickets cost $20 and same-day tickets cost $25. The total amount paid for them was $1700 both tickets. This means that
20x + 25y = 1700 - - - - - - - - - - - 1
Substituting x = 75 - y into equation 1, it becomes
20(75 - y) + 25y = 1700
1500 - 20y + 25y = 1700
- 20y + 25y = 1700 - 1500
5y = 200
y = 200/5 = 40
substituting y = 40 into x = 75 - y, it becomes
x = 75 - 40
x = 35
