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seraphim [82]
3 years ago
12

Find the value of r in (4, r), (r, 2) so that the slope of the line containing them is −53

Mathematics
2 answers:
Elan Coil [88]3 years ago
7 0

Answer:

C) 7

===========================================

Work Shown:

Use the slope formula

m = (y2-y1)/(x2-x1)

Plug in the given slope we want m = -5/3 and also the coordinates of the points. Then isolate r

m = (y2-y1)/(x2-x1)

-5/3 = (2-r)/(r-4)

-5(r-4) = 3(2-r) .... cross multiplying

-5r+20 = 6-3r

-5r+20+5r = 6-3r+5r .... adding 5 to both sides

20 = 6+2r

20-6 = 6+2r-6 ....subtracting 6 from both sides

14 = 2r

2r = 14

2r/2 = 14/2 .... dividing both sides by 2

r = 7

The slope of the line through (4,7) and (7,2) should be -5/3, let's check that

m = (y2-y1)/(x2-x1)

m = (2-7)/(7-4)

m = -5/3

The answer is confirmed

Brut [27]3 years ago
5 0

Answer:

C)  7

Correct answer

Step-by-step explanation:

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I am ab odd number i am less than 100 the sum of my digits is 12 i am a multible of 15 what number amm i
Ivan

Answer:

75

Step-by-step explanation:

7 + 5 = 12

15 x 5 = 75

3 0
3 years ago
Shannon and osaro ate dinner at olive garden Shannon meal was 12.65 and osaro meal was 21.55 if they left a 15% tip what was the
Varvara68 [4.7K]
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.15 is the percentage of the tip they pay in decimal form in order to multiply it on a calculator.
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4 0
3 years ago
A kite is tied to the ground. The rays from the sun hit the kite perpendicular to the kite string, casting a shadow of the kite
stiks02 [169]


so if you are asking for the distance do y2-y1/x2-x1

0-12/3-0

-12/3=-4

so -4 units


6 0
3 years ago
Read 2 more answers
Use a graphing calculator to solve the equation -2sin(theta)= 1.2 in the interval from 0 to 2pi.
elena-s [515]

Answer:

\theta=\pi +arcsin(\frac{3}{5})\approx 3.785\\\\\theta=2\pi -arcsin(\frac{3}{5} ) \approx 5.64  

Step-by-step explanation:

As you can see from the graph I attached you, the possible solutions in the interval from 0 to 2π are approximately:

\theta=3.7\\\\and\\\\\theta=5.7

So, it's useful to solve the equation too, in order to verify the result:

-2sin(\theta)=1.2\\\\sin(\theta)=-\frac{3}{5}

Taking the inverse sine of both sides:

\theta=\pi +arcsin(\frac{3}{5})\approx 3.785\\\\\theta=2\pi -arcsin(\frac{3}{5} ) \approx 5.64

Using this result we can conclude the solutions in the interval from 0 to 2π are approximately:

\theta\approx 3.785\\\\\theta \approx 5.64

8 0
3 years ago
Simplify please I need help don't get it
trasher [3.6K]
Hope this helps. If you have any further question ask me in comment.

4 0
3 years ago
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