$At the farthest point the velocity of particle will be zero. \ Differentiating the given equation of position and equating it with zero:$$\begin{aligned}x(t) &=5 t^{3}-9 t^{2}+7 \\x^{\prime}(t) &=15 t^{2}-18 t \\0 &=15 t^{2}-18 t \\t(15 t-18) &=0 \\t &=0 \\t &=\frac{18}{15}=1.2 \mathrm{~s}\end{aligned}$

$$$Thus, at $t=1.2 \mathrm{~s}$ particle will be at the farthest point. \\\\\underline{Justification:}\\The particle moves towards the left from $t \in[0,1.2)$. After that particle keeps moving in the positive x-direction.$

5 0

2 years ago

Explain how the evolutionary and socio-cultural perspectives might explain the use of corporal punishment on children.?

valkas [14]

Children will associate there unacceptable behaviour with getting spanked, and the purpose is to dissuade them from partaking in that behaviour in the future.

5 0

4 years ago

Read 2 more answers

Hi , i need the lenth of the square

stiks02 [169]

The length of a square is 4 times A where A is the edge length

7 0

3 years ago