In a 45-45-90 right triangle, what is the ratio of the length of one leg to the length of the other leg?

CUCI P

Free_Kalibri [48]

Answer:

$62.42

Step-by-step explanation:

1st step: Simplify the numbers first

$24.99 -------> 25

$12.99 ---------> 13

$4.49 ----------> 4

$19.95 ---------> 20

25+13+4+20= 62

cents from simplified version: 42 cents are added to the final number

$0.42+ $62.00 = $62.42

Total Cost: The four athletic items will cost $62.42 in total.

Hope this helps!!!

6 0

3 years ago

Read 2 more answers

If the length of the minute hand of the clock in London commonly known as “Big Ben” is 11.25’ from the center of the clock to th

rodikova [14]

First, we should figure out the area of the entire face of the clock because we need that information to solve the problem. The formula for the area of a circle is A=pi*r^2. Since we know that r (radius) is equal to 11.25 feet, we can plug this in for r and solve for A: A=pi*11.25^2 which equals A=397.61 ft^2 rounded to the nearest hundredth.

Now, to find the area the hand sweeps over in 5 minutes, we should determine how much of the clock the hand sweeps over in 5 minutes. Think about it like this: since 5 minutes goes into 60 minutes 12 times (60/5=12), then 5 minutes is one twelfth of the clock's face. Therefore, we are going to divide the total area by 12 (397.61/12) to get 33.13 ft^2, so the answer is C.

I hope this helps.

5 0

3 years ago

Which of these is the algebraic expression for "eight less than some number?"

kipiarov [429]

B-8 would be the answer. This is because we are saying you have 8 less than something. So no matter what something is, we are taking away 8 from it. Since our something is unknown, we use our variable 'b' in its place, and subtract 8, giving us b-8.<span />

8 0

3 years ago

The time needed to complete a final examination in a particular college course is normallydistributed with a mean of 80 minutes

Artist 52 [7]

Answer:

a) 0.023

b) 0.286

c) 10 students will be unable to complete the exam inthe allotted time.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 80 minutes

Standard Deviation, σ = 10 minutes

We are given that the distribution of time to complete an exam is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(completing the exam in one hour or less)

P(x < 60)

$P( x < 60) = P( z < \displaystyle\frac{60 - 80}{10}) = P(z < -2)$

Calculation the value from standard normal z table, we have,

$P(x < 60) =0.023= 2.3\%$

b) P(complete the exam in more than 60 minutes but less than 75 minutes)

$P(60 \leq x \leq 75) = P(\displaystyle\frac{60 - 80}{10} \leq z \leq \displaystyle\frac{75-80}{10}) = P(-2 \leq z \leq -0.5)\\\\= P(z \leq -0.5) - P(z < -2)\\= 0.309- 0.023 = 0.286= 28.6\%$