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3 years ago

8

For isosceles AJKL shown below, which of the following is the measure of ZK to the nearest tenth of a

1 answer:

Olenka [21]3 years ago

8 0

Answer:

yes yes the deegre is q5rt

Step-by-step explanation:

rfwefwefewffdsfd yes

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6.12 is Irrational

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Let u = (1, k) and v = (2, 1). Find k such that The distance between u and v is 1 u and v are orthogonal The angle between u and

SVETLANKA909090 [29]

Answer:k=1,k=-2,k= $8\pm 5\sqrt{3}$

Step-by-step explanation:

Given two vectors

$u=1\hat{i}+k\hat{j}$

$v=2\hat{i}+1\hat{j}$

$\left ( i\right )$ Distance between them is given by

$|u-v|=\sqrt{\left ( 2-1\right )^2+\left ( 1-k\right )^2}=1$

squaring both side

$1^{2}+\left ( 1-k\right )^2=1$

$k^2-2k+1=0$

$\left ( k-1\right )^2=0$

k=1

$\left ( ii\right )$

angle between u and v is 90 i.e. orthogonal

$u\dot v=0$

$\left ( 1\hat{i}+k\hat{j}\right )\dot \left ( 2\hat{i}+1\hat{j}\right )$ =0

2+k=0

k=-2

$\left ( iii\right )$

angle between u & v is $\frac{\pi }{3}$

$u\dot v=|u||v|cos\left (\frac{\pi }{3}\right )$

$|u|=\sqrt{1^2+k^2}$

$|v|=\sqrt{2^2+1^2}$

$2+k=\left ( \sqrt{1+k^2}\right )\left ( \sqrt{5}\right )cos\left ( \frac{\pi }{3}\right )$

$\left ( 4+2\right )^2=\left ( 1+k^2\right )5$

$k^2-16k-11$ =0

k= $8\pm 5\sqrt{3}$

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3 years ago

Find the value of tan theta if sin theta = 12/13 and theta is in quadrant 2

nadya68 [22]

In quadrant 2, $\sin\theta>0$ and $\cos\theta$ . Use the Pythagorean identity to establish that

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Then

$\tan\theta=\dfrac{\sin\theta}{\cos\theta}=\dfrac{\frac{12}{13}}{-\frac5{13}}=-\dfrac{12}5$

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3 years ago

Write an expression for the apparent nth term (a(n)) of the sequence. (Assume that n begins with 1.)

expeople1 [14]

Answer:

34

Step-by-step explanation:

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