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3 years ago

For isosceles AJKL shown below, which of the following is the measure of ZK to the nearest tenth of a

Mathematics

1 answer:

Olenka [21]3 years ago

8 0

Answer:

yes yes the deegre is q5rt

Step-by-step explanation:

rfwefwefewffdsfd yes

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Jack's house is located at the origin (0,0). He walks 2 blocks right. Then, he walks 6 blocks up. Finally, he walks 3 blocks rig

attashe74 [19]

Answer: 5, 6

Step-by-step explanation:

0 + 2 = 2

2 , 0

0 + 6 = 6

2, 6

2 + 3 = 5

5, 6

5 0

3 years ago

What is the probability of rolling 2 on a die

Pavlova-9 [17]

Answer:

1/6

Step-by-step explanation:

There are total of 6 numbers on a die, 1 through 6.

Getting 2 is one of the six possibilities.

Therefore, 1/6.

6 0

4 years ago

Read 2 more answers

Is 0.62 a rational number?

dimaraw [331]

A rational number is any number that can be written <em>as a ratio of two integers</em>.

0.62 fits the bill, as it can be written as the ratio 62/100 (or simplified to the ratio 31/50)

7 0

3 years ago

Read 2 more answers

Consider a Poisson distribution with μ = 6.

bearhunter [10]

Answer:

a) $P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

b) f(2) = 0.04462

c) f(1) = 0.01487

d) $P(X \geq 2) = 0.93803$

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of successes

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

In this question:

$\mu = 6$

a. Write the appropriate Poisson probability function.

Considering $\mu = 6$

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

b. Compute f (2).

This is P(X = 2). So

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

$P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.04462$

So f(2) = 0.04462

c. Compute f (1).

This is P(X = 1). So

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

$P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.01487$

So f(1) = 0.01487.

d. Compute P(x≥2)

This is:

$P(X \geq 2) = 1 - P(X < 2)$

In which:

$P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-6}*6^{0}}{(0)!} = 0.00248$

$P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.01487$

$P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.04462$

Then

$P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.00248 + 0.01487 + 0.04462 = 0.06197$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.06197 = 0.93803$

$P(X \geq 2) = 0.93803$

5 0

3 years ago

Secant DB intersects secant DZ at point D. Find the length of DY

netineya [11]

By the Intersecting Secants Theorem we have
2x(2x+7)=x(x+23)
4x^2+14x=x^2+23x
3x^2=9x
3x=9
x=3
Since DY is length 2x,
the length of DY is 6.

5 0

3 years ago