To solve for this, we need to use the Distributive Property, which allows us to multiply the number/variable outside of the parenthesis by all inside numbers/variables.
For example, 1(2+3) can be distributed by:
1(2) + 1(3), which is 2 + 3, simplified as 5.
Using the information I've provided, we can solve this.
7(4x -6) = 28
Use the Distributive Property.
7(4x) + 7(-6)
28x -42 = 28 is now our equation.
Add 42 to both sides to get 28x by itself.
28x = 70
Divide both sides by 28 to solve for x.
x = 2.5
I hope this helps!
The answer is D. You can rule out A and B by looking at the x value of 0 because the corresponding y value is 7 so you need to add 7 to a number multiplied by 0. And then you know it's not C because if you plug in the 0 for x it doesn't work.
Answer: (-2, 0) and (0, -2)
Step-by-step explanation:
This system is:
y + x = -2
y = (x + 1)^2 - 3
To solve this we first need to isolate one of the variables in one fo the equations, in the second equation we have already isolated the variable y, so we can just replace it in the first equation:
(x + 1)^2 - 3 + x = -2
Now we can solve this for x.
x^2 + 2*x + 1 - 3 = -2
x^2 + 2*x + 1 -3 + 2 = 0
x^2 + 2*x + 0 = 0
The solutions of this equation are given by the Bhaskara's formula, then the solutions are:
The two solutions are:
x = (-2 - 2)/2 = -2
In this case, we replace this value of x in the first equation and get:
y - 2 = -2
y = -2 + 2 = 4
This solution is x = -2, y = 0, or (-2, 0)
The other solution for x is:
x = (-2 + 2)/2 = 0
If we replace this in the first equation we get:
y + 0 = -2
y = -2
This solution is x = 0, y = -2, or (0, -2)
Answer:
-5r + 8r +5
= (-5+8)r+5 (we can calculate number in same variabe)
= 3r +5
hope it helps ^°^