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liberstina [14]
3 years ago
14

What is a simpler form of the following expressions?

Mathematics
1 answer:
statuscvo [17]3 years ago
6 0
J x j = j^2
j x -7 = -7j
7 x -7 = -49
j x 7 = 7j
j^2 - 7j + 7j - 49 = D = j^2 - 49
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Write as a fraction greater than 1 example 2 1/4
melomori [17]

Answer:

1<x

Step-by-step explanation:

This means any number greater than one

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3 years ago
Solve for X. I can't seem to figure out how to isolate the X. The answers of course are X = 0,2 but I need to know the process.
marin [14]
There is no algebraic way of isolating X unfortunately. 
For these equations, you have to solve with numerical approximation.
I suggest Newtons method if you know calculus.
7 0
3 years ago
Please help me
Andrej [43]
B 2/3

Solution

6÷9= 2/3
5 0
3 years ago
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A rectangular garden must have a perimeter of 160 feet and an area of at least 1300 square feet. Describe the possible lengths o
Morgarella [4.7K]

Answer: The lengths of the garden are 57.32 feet and 22.68 feet (approximately)

Step-by-step explanation: The area has been given as 1300 which means,

Area = L x W

1300 = L x W ———(1)

Also the perimeter has been given as 160, hence we also have

Perimeter = 2(L + W)

160 = 2(L + W)

80 = L + W ———(2)

From equation (2), make L the subject of the equation

L = 80 - W

Substitute for the value of L into equation (1)

1300 = L x W

1300 = (80 - W) x W

1300 = 80W - W^2

Rearranging the equation we now have;

W^2 - 80W + 1300 = 0

Since we cannot factorize we shall apply the quadratic equation formula to solve for W. Please refer to the attachment for details of this.

Having calculated the value of W to be either 57.32 or 22.68, we can now find the value of L as follows;

Substitute for the value of W into equation (1)

1300 = L x W

1300 = L x 57.32

Divide both sides of the equation by 57.32

22.68 = L.

(Note that if we take the other value of W which is 22.68, the value of L shall be 57.32)

Since the area of the rectangular garden must be AT LEAST 1300 square feet we shall use the exact values for;

Length = 57.32 feet

Width = 22.68 feet

3 0
3 years ago
Read 2 more answers
What are the steps for using a compass and straightedge to construct a regular hexagon inscribed in a circle?
N76 [4]
The steps to construct a regular hexagon inscribed in a circle using a compass and straightedge are given as follows:

1. <span>Construct a circle with its center at point H.

2. </span><span>Construct horizontal line l and point H on line l

3. </span>Label the point of intersection of the circle and line l to the left of point H, point J, and label the point of intersection of the circle and line l to the right of point H, point K.<span>

4. Construct a circle with its center at point J and having radius ​ HJ ​ . Construct a circle with its center at point K having radius ​ HJ

5. </span><span>Label the point of intersection of circles H and J that lies above line l, point M, and the point of their intersection that lies below line l, point N. Label the point of intersection of circles H and K that lies above line l, point O, and the point of their intersection that lies below line l, point P.

6. </span><span>Construct and JM⎯⎯⎯⎯⎯, MO⎯⎯⎯⎯⎯⎯⎯, OK⎯⎯⎯⎯⎯⎯⎯, KP⎯⎯⎯⎯⎯, PN⎯⎯⎯⎯⎯⎯, and NJ⎯⎯⎯⎯⎯ to complete regular hexagon JMOKPN .</span>
3 0
2 years ago
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