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3 years ago

Given the function f(x)=-3e^x^+^1, find f(x) if x=2

Mathematics

1 answer:

horrorfan [7]3 years ago

4 0

F(x) = -3e^(x + 1)
f(2) = -3e^(2 + 1) = -3e^3

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Maggie is standing on a platform that is 8 feet above the ground. She throws a ball in the air that hits the ground after 2 seco

Paha777 [63]

The equation that offers the best approximation to this result is: $h = -16\cdot t^{2}+28\cdot t + 8$ . (Choice D)

<h3>How to find the free fall formula for a given scenario</h3>

An object experiments a free fall when it is solely accelerated by gravity on the assumption of an <em>uniform</em> acceleration. The formula is described below:

$h =h_{o} + v_{o}\cdot t + \frac{1}{2}\cdot g\cdot t^{2}$ (1)

Where:

$h_{o}$ - Initial height, in feet.
$v_{o}$ - Initial speed, in feet per second.
$t$ - Time, in seconds.
$g$ - Gravitational acceleration, in feet per square second.

If we know that $t = 2\,s$ , $h_{o} = 8\,ft$ , $h = 0\,ft$ , $g = -32.174\,\frac{ft}{s^{2}}$ , then the height formula is:

$0 = 8 +2\cdot v_{o} - \frac{1}{2}\cdot (32.174)\cdot (2)^{2}$

$0 = -56.348+2\cdot v_{o}$

$v_{o} = 28.174\,\frac{ft}{s}$

The equation that offers the best approximation to this result is: $h = -16\cdot t^{2}+28\cdot t + 8$ . (Choice D)

To learn more on free fall, we kindly invite to check this verified question: brainly.com/question/13796105

5 0

3 years ago

In figure above, if l1 | | l2 then value of x is:<br> a) 40°<br> b) 50°<br> c) 80°<br> d) 100°

cupoosta [38]

Answer:

its letter c so 80

Step-by-step explanation:

I hope this help

3 0

3 years ago

HELP! 40 points!

Vitek1552 [10]

Y-14=12# x+1 answer of math

7 0

3 years ago

Read 2 more answers

What is the answer to 24=2k

Ilya [14]

Well, as you can see the answer and problem are switched so u do this

24=2k
÷2 ÷2
----------------------
12=k. check:

12×2 is 24☆

happy to help.

8 0

3 years ago

A sphere has a diameter of 4 x 10^-3 mm. What is the approximate volume of the sphere? Use 3.14 for pi.

kolezko [41]

Answer:

$3.349 \times {10}^{ - 10} \: {mm}^{3}$

Step-by-step explanation:

$d = 4 \times {10}^{ - 3} \: mm \\ r = 2 \times {10}^{ - 3} \: mm \\ V_{sphere} = \frac{4}{3} \pi {r}^{3} \\ = \frac{4}{3} \times 3.14 \times {(2 \times {10}^{ - 3} )}^{3} \\ = \frac{4}{3} \times 3.14 \times 8\times {10}^{ - 9} \\ = \frac{100.48}{3} \times {10}^{ - 9} \\ = 33.4933333\times {10}^{ - 9} \\ = 33.49 \times {10}^{ - 9} \\ = 3.349 \times {10}^{ - 10} \: {mm}^{3}$

8 0

3 years ago