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frosja888 [35]
3 years ago
12

Compute the values of dy and Δy for the function y=e^(2x)+6x given x=0 and Δx=dx=0.03.

Mathematics
1 answer:
Maksim231197 [3]3 years ago
6 0

Answer:

  • dy = 8·dx
  • Δy = 0.24

Step-by-step explanation:

The derivative of your function is ...

  y' = dy/dx = 2e^(2x) +6

At x=0, the value is ...

  y'(0) = 2e^0 +6 = 8

  dy = 8·dx

__

  Δy = y'(0)·Δx

  Δy = 8(.03)

  Δy = 0.24

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5 0
3 years ago
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Black_prince [1.1K]
Thanks for the question!

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Hope this helps!
4 0
3 years ago
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Suppose you take the small prism and stack it on top of the larger prism. What will be the volume of the composite figure?
Degger [83]
Find the volume of the first figure, then find the volume of the second figure, then add them together.
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--------------------------------------------
1,080+432= 1,512 in^3
--------------------------------------------
Your answer should be 1,512
3 0
4 years ago
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