Compute the values of dy and Δy for the function y=e^(2x)+6x given x=0 and Δx=dx=0.03.
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Answer:
Step-by-step explanation:
Hi there!
We are given the points (6,0) and (0, -5), and we want to write the equation of the line containing those points in slope-intercept form
Slope-intercept form can be written as y=mx+b, where m is the slope and b is the y intercept
First, we need to find the slope of the line
The formula for the slope can be written as , where
and
are points
We have everything we need to find the slope, but let's label the points to avoid confusion
Now substitute these values into the formula
m=
m=
Subtract
m=
Simplify
m=
The slope of the line is 5/6
Let's plug this value into the formula for the equation of the line in slope-intercept form.
We substitute 5/6 for m in y=mx+b:
y=
Now we need to find b
As stated before, b is the y intercept, which is the value where the line hits the y axis. The value of x at the y intercept is 0.
One of the points we were given is actually the y intercept; that point is (0, -5); notice how the value of x in this point is 0
The value of b is the value of y in this point, which is -5 in this case.
Substitute -5 as b in the formula.
Hope this helps!
See more on this subject here (n.b. the answer uses a different way of solving): brainly.com/question/20891204
Pythagorean Theorem: a^2+b^2=c^2
(9)^2 + b^2 = (23)^2
81 + b^2 = 529
b^2 = 529 - 81
b^2 = 448
b^2 =
b = 21.2
(9)^2 + b^2 = (23)^2
81 + b^2 = 529
b^2 = 529 - 81
b^2 = 448
b^2 =
b = 21.2