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frosja888 [35]
3 years ago
12

Compute the values of dy and Δy for the function y=e^(2x)+6x given x=0 and Δx=dx=0.03.

Mathematics
1 answer:
Maksim231197 [3]3 years ago
6 0

Answer:

  • dy = 8·dx
  • Δy = 0.24

Step-by-step explanation:

The derivative of your function is ...

  y' = dy/dx = 2e^(2x) +6

At x=0, the value is ...

  y'(0) = 2e^0 +6 = 8

  dy = 8·dx

__

  Δy = y'(0)·Δx

  Δy = 8(.03)

  Δy = 0.24

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We want to evaluate how much money would be in your account after the third year, to do it we must put t = 3 in our function, then

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A number consist of 2 digits whose sum is 8, If 8 is subtracted from the number, the digits interchange their place. The number
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Step-by-step explanation:

Let's say the two digit number is 10x + y, where x is the first digit and y is the second digit.

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8 0
3 years ago
Read 2 more answers
2 - 3d = 4d - 19<br><br>Answer and show steps​
defon

2 - 3d = 4d - 19

Add the opposite to both sides to get the variable on the left side only.

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Hope I helped :)

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