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cupoosta [38]
3 years ago
12

Can someone help me with this please?​

Mathematics
1 answer:
Vladimir79 [104]3 years ago
6 0
With what? Don’t see anything
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Please help, I am so confused. Find the missing length indicated.
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Answer:

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Step-by-step explanation:

In a right triangle the hypotenuse which is 16+9 =25 has to be the largest side.  Since x is not the hyportenuse it has to be lower which only leaves one answer : 15

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During a recent eruption, the volcano spewed out copious amount of ash. One small piece of ash was ejected from the volcano with
nlexa [21]
For question number 1:The plot H = H(t) is the parabola and it reaches its maximum in the moment when exactly at midpoint between the roots t = 0 and t = 23. At that moment t = 23/2 or 11.5 seconds.
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For question number 3:H(t) = 0,   or, which is the same as -16t^2 + 368t = 0.Factor the left side to get  -16*t*(t - 23) = 0.t = 0, relates to the very start of the process, when the ash started its way up.The other root is t = 23 seconds, and it is precisely the time moment when the bit of ash will go back to the ground.
6 0
3 years ago
Geometry help please.
m_a_m_a [10]
The answer is D.) (4,3) 

trace the line to where the middle of the point looks to be and then find the point. in this instance the segment is 12 points long so the middle would be at six but because it is shifted over to the left 2 points the x coordinate would be 4. Since the line is parallel with the x axis you know that the y coordinate has to be 3. So the answer is (4,3)
4 0
4 years ago
The median of Rae's data is 2.22 minutes, and the median of Doris' data is 2.14 minutes. The interquartile range for Rae is , an
JulsSmile [24]

Complete question :

Rae and Doris are training to swim a 200-meter freestyle race. The table lists their practice times during training camp.

Rae’s Times(minutes)-2.12, 2.01, 2.46, 2, 2.22, 2.31, 2.23

doris times(minutes)-2.32, 2.19, 2.26, 2.03, 2.11, 2.14, 2.07

The median of Raes data is(drop down box answers, 2,2.03,2.14,2.22)minutes,and the median of doris data is(drop down box answers, 2,2.03,2.14,2.22)minutes. The interquartile range for rae is(drop down box answers, 0.01,0.13,0.26,0.30), and the interquartile range for doris is(drop down box answers, 0.02,0.06,0.18,0.19). The two data sets overlap(drop down box answers,very little, a lot

Answer:

Rae's median = 2.22

Rae's IQR = 0.30

DORIS median = 2.14

Doris IQR = 0.19

Step-by-step explanation:

Given :

Rae's time :

Ordered data : 2, 2.01, 2.12, 2.22, 2.23, 2.31, 2.46

Median = 1/2(n+1)th term ; n = 7

Median = 1/2(8) = 4th term

Median = 2.22

Q1 = 1/4(8)th term

Q1 = 2nd term = 2.01

Q3 = 3/4(n + 1)th term

Q3 = 3/4(8)th term

Q3 = 6th term = 2.31

Interquartile range = Q3 - Q1 = 2.31 - 2.01 = 0.30

DORIS Data:

Ordered data: 2.03, 2.07, 2.11, 2.14, 2.19, 2.26, 2.32

Median = 1/2(n+1)th term ; n = 7

Median = 1/2(8) = 4th term

Median = 2.14

Q1 = 1/4(8)th term

Q1 = 2nd term = 2.07

Q3 = 3/4(n + 1)th term

Q3 = 3/4(8)th term

Q3 = 6th term = 2.26

Interquartile range = Q3 - Q1 = 2.26 - 2.07 = 0.19

6 0
3 years ago
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