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Liula [17]
3 years ago
12

A tin is a right circular cylinder with a diameter of 4 meters and a height of 6 meters. What is the surface area of this tin, i

n terms of pi?
Mathematics
1 answer:
agasfer [191]3 years ago
4 0

Answer:

32 pi m^2

Step-by-step explanation:

The surface area of a cylinder is given by

SA = 2pi r^2 + 2 pi rh

   The diameter is 4 meters so the radius is 1/2 of the diameter = d/2 = 2 meters

SA = 2 * pi * (2)^2 + 2 pi *2*6

    = 8pi +24pi

   = 32 pi m^2

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What is the range of the relation? {(1, 2), (2, 4), (3, 2), (4, 6)}  A.{2, 4}  B.{1, 2, 3, 4, 6}  C.{2, 4, 6}  D.{1, 2, 3, 4}
tamaranim1 [39]
(1)\ \ \ \ range:\ \ \ \{2, 4, 6\}\ \ \ \Rightarrow\ \ \ Ans.\ C\\\\(2)\ \ \ function:\ \ \ \{(1, 2); (2, 2); (3, 2); (4, 2)\}\ \ \ \Rightarrow\ \ \ Ans.\ D\\\\(3)\ \ \ f(4)=2-3\cdot4=2-12=-10\ \ \ \Rightarrow\ \ \ Ans.\ C\\\\(4)\ \ \ direct:\ \ \ y=ax\ \ \ \Rightarrow\ \ \ y= \frac{1}{3} x\ \ \ \Rightarrow\ \ \ Ans.\ B\\\\(5)\ \ \ f(x)=ax\ \ \ and\ \ \ f(4)=12\\.\ \ \ \ \ \Rightarrow\ \ \ 12=a\cdot4\ \ \ \Rightarrow\ \ \ a=3\ \ \ \Rightarrow\ \ \ f(x)=3x\ \ \ \Rightarrow\ \ \ Ans.\ (?)\\\\

(6)\ \ \ f(x)=ax^2\ \ \ and\ \ \ f(2)=48\\.\ \ \ \Rightarrow\ \ 48=a\cdot2^2\ \ \Rightarrow\ \ a=48:4=12\ \ \Rightarrow\ \ f(x)=12x^2\ \Rightarrow\ \ Ans.\ C\\\\(7)\ \ \ inversely:\ \ \ f(x)= \frac{a}{x} \ \ \ and\ \ \ f(2)=4\\.\ \ \ \Rightarrow\ \ \ 4= \frac{a}{2} \ \ \ \Rightarrow\ \ \ a=4\cdot2=8\ \ \ \Rightarrow\ \ \ y= \frac{8}{x}\ \ \ \Rightarrow\ \ \ Ans.\ B
5 0
3 years ago
An amusement park studied methods for decreasing the waiting time (minutes) for rides by loading and unloading riders more effic
Digiron [165]

Answer:

see explaination

Step-by-step explanation:

The p-value for Factor A is greater than 0.1

What is your conclusion with respect to Factor A?

Factor A is not significant.

The p-value for Factor B is greater than 0.1

What is your conclusion with respect to Factor B?

Factor B is not significant.

The p-value for the interaction of factors A and B is greater than 0.1

What is your conclusion with respect to the interaction of Factors A and B?

The interaction of Factors A and B is not significant.

What is your recommendation to the amusement park?

Since method is not a significant factor, use either loading and unloading method.

4 0
3 years ago
Factor 6x4 – 5x2 + 12x2 – 10 by grouping. What is the resulting expression?
VARVARA [1.3K]
I hope this helps you

8 0
3 years ago
Read 2 more answers
Please help me :/!!!!
Dovator [93]

Answer:

(3, 9)

Step-by-step explanation:

Set 3x and 2x+3 equal to each other forming an equation in x.

3x=2x+3

Solve for x.

x=3

Substitute the given value of x into the equation y=3x.

y=3x3

Solve for y.

y=9

(x, y) = (3, 9)

Hope this helps :)

7 0
3 years ago
Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1
sleet_krkn [62]

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}

From Left side:

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)

\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}

NOTE: sin²θ + cos²θ = 1

\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{2}{sin^2\theta-cos^2\theta}

\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}

\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}

\dfrac{2sec^2\theta}{tan^2\theta-1}

Left side = Right side <em>so proof is complete</em>

8 0
3 years ago
Read 2 more answers
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