Answer:
300 students are enrolled.
Step-by-step explanation:
As the university accepts 60% of the students who apply.
As 2000 students apply, it means that:
2000 × 60% ⇒ 2000 × 0.6 = 1200 students are accepted
Out of these 1200, 25% enrolled
1200 × 25% ⇒ 1200 × 0.25 = 300 students are enrolled
Therefore, 300 students are enrolled.
XYR=36 hope this helps I actually don't know if it is right so I'm so sry if it is wrong so sry
For the first digit, you have two possible choices: 1 or 2. For *each* of those choices, you can choose 1 or 2 for the second digit in the number, and for each of *those*, you can choose 1 or 2 for the third digit of the number.
That’s 2 * 2 * 2 or 8 possible 3-digit numbers you can make with the digits 1 and 2.
Use the z-score:
112 - 100
For 112, the z-score is --------------- = 12/15, or 0.8.
15
Next, find the AREA under the standard normal curve TO THE LEFT OF 0.8.
Use either a z-score table or a calculator for this purpose.
Using my calculator, I found that this area is 0.532. That places 112 in the 53rd percentile.
82 would be in a lower percentile: the 12th percentile.
Let me know if you have questions about how to use a calculator to do these calculations.
The answer is no.
Explanation:
60/55=1.090
7/42=.166
Therefore,
60/55≠7/42
