Answer:
![\tt x^2+3xy+4y^2](https://tex.z-dn.net/?f=%5Ctt%20x%5E2%2B3xy%2B4y%5E2)
Step-by-step explanation:
![\tt(x-2y)^2+7xy\\\\=x^2-4xy+4y^2+7xy\\\\=x^2+3xy+4y^2](https://tex.z-dn.net/?f=%5Ctt%28x-2y%29%5E2%2B7xy%5C%5C%5C%5C%3Dx%5E2-4xy%2B4y%5E2%2B7xy%5C%5C%5C%5C%3Dx%5E2%2B3xy%2B4y%5E2)
Answer:
No, because a x-value repeats.
Step-by-step explanation:
A function has x-values that correspond to exactly one y-value. In the given table, <u>the number '5' appears twice as an x-value</u>. This means that the relation is not a function, "because one x-value corresponds to two different y-values."
Answer:
It will take 30 minutes!
Hope this helps! :D
Step-by-step explanation:
Answer:
Step-by-step explanation:
just imagine you are on a number line and the numbers are
-5....-4.....-3.....-2....-1....0....1....2.....3
as you see the midpoint is -1