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3 years ago

15

Fifteen DVDs are to be arranged on a shelf. 4 of the DVDs are horror films, 6 are comedies, and 5 are science fiction. In how ma

ny ways can the DVDs be arranged if DVDs of the same genre must be placed together?

1 answer:

lord [1]3 years ago

4 0

Answer:

I believe it is 6 .........

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I need help with this

netineya [11]

Answer:

1. -9

2. -2

3. -3

4. 2 (positive)

Step-by-step explanation:

positive + negative= positive

negative + positive =negative

positive +positive =positive

negative +negative =negative

hope you like it ( ' - ' )

4 0

3 years ago

Read 2 more answers

Two groups of workers are painting a bridge in the bay. The first group is responsible for painting the north side of the bridge

artcher [175]

Answer:

They will each have painted 8 km. This goal will be met on Day 4.

Step-by-step explanation:

Group A | Group B

Start: 2 | Start: 5 Day 1

2 + 2 = 4 | 5 + 1 = 6 Day 2

4 + 2 = 6 | 6 + 1 = 7 Day 3

6 + 2 = 8 | 7 + 1 = 8 Day 4

4 0

3 years ago

A social scientist wishes to conduct a survey. She plans to ask a yes/no question to a random sample from the U.S. adult populat

agasfer [191]

Answer:

The sample proportion from the sample of 900 is more likely to be close to the true population proportion, p.

Step-by-step explanation:

for the first one

6 0

3 years ago

Read 2 more answers

Mia used 3 different base 10 blocks to model a 3 digit number what is the number?

spin [16.1K]

Answer:

I think its 300

but wouldn't that be like a 2 digit number like 30? scince they are only 10 blocks 10 + 10 + 10 (3×10= 30)

If you dont understand just coment.

5 0

3 years ago

Read 2 more answers

F(t)=t^2+19t+60<br> What are the zeros of the function and what is the vertex of the parabola?

SVEN [57.7K]

Answer: $-4,-15;\ \left(-\dfrac{19}{2},-\dfrac{121}{4}\right)$

Step-by-step explanation:

Given

Function is $F(t)=t^2+19+60$

Zeroes of the function are

$t^2+19t+60=0\\\\\Rightarrow t=\dfrac{-19\pm\sqrt{19^2-4\times 1\times 60}}{2\times 1}\\\\\Rightarrow t=\dfrac{-19\pm \sqrt{121}}{2}\\\\\Rightarrow t=\dfrac{-19\pm 11}{2}\\\\\Rightarrow t=-4,-15$

Using completing the square method

$y=t^2+2\times \dfrac{19}{2}t+\dfrac{19^2}{2^2}-\dfrac{19^2}{2^2}+60\\\\y=\left(t+\dfrac{19}{2}\right)^2+60-\dfrac{361}{4}\\\\y=\left(t+\dfrac{19}{2}\right)^2-\dfrac{121}{4}\\\\y+\dfrac{121}{4}=\left(t+\dfrac{19}{2}\right)^2\\\\\left(y-(-\dfrac{121}{4}\right)=\left(t-(-\dfrac{19}{2})\right)^2\\\\\text{The vertex is }\left(-\dfrac{19}{2},-\dfrac{121}{4}\right)$

4 0

3 years ago