Prime factorization of 620:
620
2 310
2 155
5 31
31 1
To write it in simplest form, you must find a common factor.
In
, 3 is a factor of both 3 and 9
3÷3=1 and 9÷3=3
So
is your answer in simplest form.
Answer:
no is not fully correct for the name part you need to put the names of the elements in the compound
Step-by-step explanation:
Infinite
x=-5y+3 is the same as x+5y=3
<span>a2 – b2 = (a + b)(a – b) or (a – b)(a + b).
This is the 'Difference of Squares' formula we can use to factor the expression.
In order to use the </span><span>'Difference of Squares' formula to factor a binomial, the binomial must contain two perfect squares that are separated by a subtraction symbol.
</span><span>x^2 - 4 fits this, because x^2 and 4 are both perfect squares, and they are separated by a subtraction symbol.
All you do here to factor, is take the square root of each term.
√x^2 = x
√4 = 2
Now that we have our square roots, x and 2, we substitute these numbers into the form (a + b)(a - b).
</span>
<span>(a + b)(a - b)
(x + 2)(x - 2)
Our answer is final </span><span>(x + 2)(x - 2), which can also be written as (x - 2)(x + 2), it doesn't make a difference which order you put it in.
Anyway, Hope this helps!!
Let me know if you need help understanding anything and I'll try to explain as best I can.</span>
