I’m pretty sure it’s line graph, if not that, bar graph
Hope this helps :D
Answer:B
Step-by-step explanation:
I’m not sure why
The same way you solve any other math problem:
You use the information you're given, and all the formulas, equations, and rules
that you know that might connect what you're given to what you need to find, and
then choose the best one to find the missing answer from the given information.
Answer:
See answer below
Step-by-step explanation:
This is a separable equation, so we solve it like this:

Then
for any constant k (this is the general solution). This solution is defined in (-∞,∞) (there are no singularities) and when x tends to infinity, no terms of the solution vanish, hence there are no transient terms.
Check the picture below.
let's notice the "white" ∡1 is an inscribed angle with an intercepted arc of (x-32), and the "green" ∡5 is also an inscribed angle with an intercepted arc of (2x).
the ∡6 and ∡2 are both external angles, however they intercepted two arcs, a "far arc" and a "near arc", thus we'll use the far arc - near arc formula, as you see in the picture, and we'll use the inscribed angle theorem for the other two.
![\bf \measuredangle 1=\cfrac{x-32}{2}\implies \measuredangle 1 =\cfrac{32}{2}\implies \measuredangle 1 = 16 \\\\[-0.35em] ~\dotfill\\\\ \measuredangle 5 =\cfrac{2x}{2}\implies \measuredangle 5 = x\implies \measuredangle 5 = 64 \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cmeasuredangle%201%3D%5Ccfrac%7Bx-32%7D%7B2%7D%5Cimplies%20%5Cmeasuredangle%201%20%3D%5Ccfrac%7B32%7D%7B2%7D%5Cimplies%20%5Cmeasuredangle%201%20%3D%2016%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cmeasuredangle%205%20%3D%5Ccfrac%7B2x%7D%7B2%7D%5Cimplies%20%5Cmeasuredangle%205%20%3D%20x%5Cimplies%20%5Cmeasuredangle%205%20%3D%2064%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf \measuredangle 2 = \cfrac{(2x+8)~~-~~(x-32)}{2}\implies \measuredangle 2=\cfrac{2x+8-x+32}{2} \\\\\\ \measuredangle 2=\cfrac{x+40}{2}\implies \measuredangle 2=\cfrac{104}{2}\implies \measuredangle 2=52 \\\\[-0.35em] ~\dotfill\\\\ \measuredangle 6=\cfrac{[(2x+8)+(x)]~~-~~(2x)}{2}\implies \measuredangle 6=\cfrac{3x+8-2x}{2}\implies \measuredangle 6=\cfrac{x+8}{2} \\\\\\ \measuredangle 6=\cfrac{72}{2}\implies \measuredangle 6=36](https://tex.z-dn.net/?f=%5Cbf%20%5Cmeasuredangle%202%20%3D%20%5Ccfrac%7B%282x%2B8%29~~-~~%28x-32%29%7D%7B2%7D%5Cimplies%20%5Cmeasuredangle%202%3D%5Ccfrac%7B2x%2B8-x%2B32%7D%7B2%7D%20%5C%5C%5C%5C%5C%5C%20%5Cmeasuredangle%202%3D%5Ccfrac%7Bx%2B40%7D%7B2%7D%5Cimplies%20%5Cmeasuredangle%202%3D%5Ccfrac%7B104%7D%7B2%7D%5Cimplies%20%5Cmeasuredangle%202%3D52%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cmeasuredangle%206%3D%5Ccfrac%7B%5B%282x%2B8%29%2B%28x%29%5D~~-~~%282x%29%7D%7B2%7D%5Cimplies%20%5Cmeasuredangle%206%3D%5Ccfrac%7B3x%2B8-2x%7D%7B2%7D%5Cimplies%20%5Cmeasuredangle%206%3D%5Ccfrac%7Bx%2B8%7D%7B2%7D%20%5C%5C%5C%5C%5C%5C%20%5Cmeasuredangle%206%3D%5Ccfrac%7B72%7D%7B2%7D%5Cimplies%20%5Cmeasuredangle%206%3D36)