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sdas [7]
3 years ago
14

What does the weight of Earth compared to the weight of Mars

Mathematics
1 answer:
melomori [17]3 years ago
7 0
Since Mars has less mass than Earth, the surface gravity on Mars is less than the surface gravity on Earth. The surface gravity on Mars is only about 38% of the surface gravity on Earth, so if you weigh 100 pounds on Earth, you would weigh only 38 pounds on Mars.
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X -5x -14=0 quadratic formula
Oksanka [162]
No its a negitive number one x minus five x's equal -14
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3 years ago
Find the slope Y=5x+12
NikAS [45]

Answer: The slope = 5.

Step-by-step explanation:

The equation of a line in the slope -intercept form is given by :-

y=mx+c

,where  m= slope , c= y-intercept.

The slope of a line represents the rate of change of y with respect to x.

Given: Equation of line : Y= 5x+12

Here Slope (m)=5

Hence, the slope = 5.

6 0
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Kon'nichiwa !!<br><br>What's the Value of <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20-%203%20%5Ctimes%20-%20%203%7D%2
NeX [460]

Answer:

3 answer

Step-by-step explanation:

hope it helps!!!

3 0
3 years ago
Read 2 more answers
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ivanzaharov [21]

Answer: 3:2

Step-by-step explanation:

the base ratio of unused tape to used tape is 24:16.

then we have to simplify,

both 16 and 24 can be divided by eight,

24 divided by eight is 3

16 divided by eight is 2

therefore, our simlpified ratio is 3:2

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5 0
3 years ago
A coin is tossed 8 times. What is the probability of getting all heads? Express your answer as a simplified fraction or a decima
kumpel [21]

Answer:

The probability of getting all heads is \frac{1}{256}.

Step-by-step explanation:

For each time the coin is tossed, there are only two possible outcomes. Either it is heads, or it is not. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

A coin is tossed 8 times. This means that n = 8

In each coin toss, heads or tails are equally as likely. So p = \frac{1}{2}

What is the probability of getting all heads?

This is P(X = 8)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

[tex]P(X = 8) = C_{8,8}*(\frac{1}{2})^{8}*(1 - \frac{1}{2})^{0} = \frac{1}{256}

The probability of getting all heads is \frac{1}{256}.

7 0
3 years ago
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