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Vladimir79 [104]
3 years ago
15

The exclamation point (!) on a billboard consists of a circle sector and circle. The radius of the sector is 9 ft, and the radiu

s of the circle is 1.5 ft. The angle of the sector is 24°. What is the total area of the exclamation point on the billboard? Round to the nearest tenth.
Mathematics
1 answer:
harina [27]3 years ago
8 0

Answer:

  24.0 square feet

Step-by-step explanation:

The area of the sector is given by ...

  A = (1/2)r²θ . . . . . where θ is the angle in radians

The area of the circle is the same, with θ=2π, so is ...

  A = πr²

__

In this problem, the area of the sector is ...

  A = (1/2)(9 ft)²(24π/180) = 27π/5 ft² ≈ 16.9646 ft²

The area of the circle is ...

  A = π(1.5 ft)² = 9π/4 ft² ≈ 7.0686 ft²

Then the total area of the exclamation point is ...

  16.9646 +7.0686 ≈ 24.0 . . . ft²

The area is about 24.0 square feet.

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6 x^{6}/3x = 2 x^{5} \\  \\ 6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2 - 6 x^{6} -2 x^{5} = 3x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2\\

We repeat previous steps until we run out of numbers:
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We are left with a number that has no x inside. This is remainder.
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