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andrezito [222]
2 years ago
15

QUICK HELP ILL GIVE BRAINLIEST

Mathematics
2 answers:
Zigmanuir [339]2 years ago
6 0

Answer:

When I first saw you... and you act like a baka..

Step-by-step explanation:

zmey [24]2 years ago
4 0

Answer:

I am on school computer, I cannot see the question. could you please type it?

Step-by-step explanation:

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.jh ip i pk ih ih i i pi ih ih hjk i i ihh k k
Aleonysh [2.5K]

Answer:

k k hhi i i kjh hi hi pi i i hi hi kp i pi hj

7 0
3 years ago
Read 2 more answers
I need help I don’t understand it
tiny-mole [99]
Shidddd lil buddy, try the 3rd one
4 0
3 years ago
I need help with this question
Nastasia [14]

Answer:

120 cm³

Step-by-step explanation:

V = (1/3)×base area×height

  = (1÷3)×(4×9)×10

  =120

8 0
3 years ago
Use the work shown below to find the simplified product. StartFraction 25 x squared Over 2 x + 6 EndFraction times StartFraction
Leya [2.2K]

Answer:

It’s C. 5x/x+3

Step-by-step explanation:

Just trust me

6 0
3 years ago
Which pair of complex numbers has a real-number product? (1 + 3i)(6i) (1 + 3i)(2 – 3i) (1 + 3i)(1 – 3i) (1 + 3i)(3i)
Kobotan [32]

Answer:

<h2>(1 + 3i)(1 – 3i) gives real number product</h2>

Step-by-step explanation:

Given the expressions

(1 + 3i)(6i) ,(1 + 3i)(2 -3i), (1 + 3i)(1 - 3i), (1 + 3i)(3i)

From analysis one of the following pairs has real-number products

(1 + 3i)(2 -3i), (1 + 3i)(1 - 3i)

Performing operations on

(1 + 3i)(2 -3i)= 2-3i+6-6i^2 \\= 2-3i+6-6(-1) \\=2-3i+6+6 \\=14-3i

Performing operations on

(1 + 3i)(1 - 3i) \\= 1-3i+3i-9(i)^2 \\= 1+0-9(-1) \\= 1+9=10

6 0
3 years ago
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