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castortr0y [4]
3 years ago
6

You add 4 foot section of land to a 6 six foot by 8 foot garden. Find the area of the new garden

Mathematics
1 answer:
Makovka662 [10]3 years ago
7 0
Area = W x L
The area of the new garden depends on how the 4 foot section is added.
If added to the 6 foot side, the 6 foot becomes 10 feet and the area would be 80 sq feet.  
But it is perhaps more likely the 8 foot side was lengthened to 12 feet and the new garden would have an area of 72 sq feet.
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Which of the following is equal to the fraction below ?<br><br> (answers are in the picture)
sattari [20]
The answer is B since (5/9)^8 = 5^8/9^8
5 0
2 years ago
What are the zeros of the function?
castortr0y [4]
Try this explanation:
if to re-write the function f(x)=x(x²-x-6), then to make up the equation x(x²-x-6)=0, it is possible to find the zeros requred:
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4 0
3 years ago
Read 2 more answers
Change at least one number in the table so that it DOES represent a function.
almond37 [142]

Answer:

change 2 to 4

and 1 to 5

1 --> 5

2 --> 10

3 --> 15

4 --> 20

5 --> 24

Step-by-step explanation:

Function means you can have one input for evry one output

so you have to change the 2 and 1 to diffrent numbers like 4 and 5

so now evey imput has their own out put

befor input one it had 5 and 24

and input two had 10 and 20 but changing the number you get one for one

6 0
3 years ago
I need help with how to solve this problem. It is #14. It already shows the answer (1point) but I need help on how to get there
Hitman42 [59]

Answer:

Option 4: 0.554

Step-by-step explanation:

As we can see that the intervals and their frequencies are given.

We have to calculate the probability of students' score falling between 70 and 89. It will use the frequency of both intervals 70-79 and 80-89.

So, combined scores of both intervals are:

172+105 = 277

Now to find the probability

= 277/500

=0.554

So option no 4 is the correct answer ..

7 0
3 years ago
The position vector for a particle moving on a helix is
topjm [15]

Answer:

a) 25.15

b)

   x = 1

   y = t

   z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)

c) (x,y) = (1, -2pi)

Step-by-step explanation:

a)

First lets calculate the velocity, that is, the derivative of c(t) with respect to t:

v(t) = (-sin(t), cos(t), 2t)

The velocity at t0=4pi is:

v(4pi) = (0, 1, 8pi)

And the speed will be:

s(4pi) = √(0^2+1^2+ (8pi)^2) = 25.15

b)

The tangent line to c(t) at t0 = 4pi has the parametric form:

(x,y,z) = c(4pi) + t*v(4pi)

Since

 c(4pi) = (1, 0, (4pi)^2)

The tangent curve has the following components:

x = 1

y = t

z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)

c)

The intersection with the xy plane will occurr when z = 0

This happens at:

  t1 = -2pi

Therefore, the intersection will occur at:

(x,y) = (1, -2pi)

6 0
3 years ago
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