Eli is 17 years old because 17-4=13
and 17+13=30
Answer:
A. 100$
Step-by-step explanation:
take 125 and multiply it to .20 (this is 20% in decimal form) this gives you 25. you know subtract 25 from 125 which gives you 100.
Answer:
d)
Step-by-step explanation:
The domain are all the possible values for x. For this graph the domain will continue on forever in both the positive and negative direction, so (-∞, ∞).
The range are all possible values for y. For this graph, k affects the height of the graph. Since k affects how far up/ down you move the graph, therefore (k, ∞)
The h in the equation shows how far you move the graph to the left/right.
For the fulcrum to balance, the product of weight and distance on both sides of the fulcrum must be the same.
Let d1= x. since total distance is 12, we can write d2 = 12 - x
for the fulcrum to balance:
60x = 50(12 - x)
60x = 600 - 50x
110x = 600
x = 5.45
Thus, d1= 5.45
and
d2= 12 - d1 = 12 - 5.45 = 6.55
d1 = 5.45
d2 = 6.55
Answer:
(x,y,z) = (5/2, 5/2, 0)
If z = t,
(x,y,z) = ((5-3t)/2, (5-t)/2, t)
Step-by-step explanation:
-x + y - z = 0
2y + z = 5
(1/5)z = 0
From eqn 3, z = 0
2y + z = 5
Substitute for z in eqn 2
2y + 0 = 5
y = 5/2
substituting for y and z in eq 1
-x + (5/2) - 0 = 0
x = (5/2)
(x,y,z) = (5/2, 5/2, 0)
In terms of t, if z = t,
eqn 2 becomes 2y + t = 5
2y = 5 - t
y = (5 - t)/2
Eqn1 becomes
-x + (5-t)/2 - t = 0
-x + (5/2) - (t/2) - t = 0
-x + (5/2) - (3t/2) = 0
x = (5-3t)/2
(x,y,z) = ((5-3t)/2, (5-t)/2, t)