Answer:
Solution:-
Step-by-step explanation:
given ,
mass (m) =2000kg
velocity (v) = 35m/s
now ,
momentum (p) = m×v
=2000×35
= 70000 kg . m/s .|
25/45 45 divided by 27
that is .6 make it a percent by moving to decimal places to the right
60.00
60%
The denominator of the first term is a difference of squares, such that
4<em>a</em> ² - <em>b</em> ² = (2<em>a</em>)² - <em>b</em> ² = (2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>)
So you can write the fractions as
(4<em>a</em> ² + <em>b</em> ²)/((2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>)) - (2<em>a</em> - <em>b</em>)/(2<em>a</em> + <em>b</em>)
Multiply through the second fraction by 2<em>a</em> - <em>b</em> to get a common denominator:
(4<em>a</em> ² + <em>b</em> ²)/((2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>)) - (2<em>a</em> - <em>b</em>)²/((2<em>a</em> + <em>b</em>) (2<em>a</em> - <em>b</em>))
((4<em>a</em> ² + <em>b</em> ²) - (2<em>a</em> - <em>b</em>)²) / ((2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>))
Expand the numerator:
(4<em>a</em> ² + <em>b</em> ²) - (2<em>a</em> - <em>b</em>)²
(4<em>a</em> ² + <em>b</em> ²) - (4<em>a</em> ² - 4<em>ab</em> + <em>b</em> ²)
4<em>ab</em>
<em />
So the original expression reduces to
4<em>ab</em> / ((2<em>a</em> - <em>b</em>) (2<em>a</em> + <em>b</em>))
or
4<em>ab</em> / (4<em>a</em> ² - <em>b</em> ²)
upon condensing the denominator again.
Answer: There are 4 possibilities. They are all listed below with their percents.
You can create a tree diagram to shows all of the possibilities. It will start with 2 branches and then each of those branches will have 2 branches.
The possibilities are: UU, UD, DU, DD
To find the probabilities of each, you have to multiply the percent for each together.
UU = 0.66 x 0.66 = 0.4356
UD = 0.66 x 0.34 = 0.2244
DU = 0.34 x 0.66 = 0.2244
DD = 0.34 x 0.34 = 0.1156
Answer:
(b) (c) (a)
Step-by-step explanation:
Standard Normal distribution has a higher peak in the center, with more area in this región, hence it has less area in its tails.
Student's t-Distribution has a shape similar to the Standard Normal Distribution, with the difference that the shape depends on the degree of freedom. When the degree of freedom is smaller the distribution becomes flatter, so it has more area in its tails.
Student's t-Distributionwith 1515 degrees of freedom has mores area in the tails than the Student's t-Distribution with 2020 degrees of freedom and the latter has more area than Standard Normal Distribution
