(a) 1,1 (b) 3,2 (c) 3,2 (d) 1,5
Answer:

Step-by-step explanation:
We want to write an exponential function that goes through the points (0, 20) and (6, 1280).
The standard exponential function is given by:

The point (0, 20) tells us that <em>y</em> = 20 when <em>x</em> = 0. Hence:

Simplify:

So, our exponential function is now:

Next, the point (6, 1280) tells us that <em>y</em> = 1280 when <em>x</em> = 6. Thus:

Solve for <em>b</em>. Divide both sides by 20:

Therefore:
![b=\sqrt[6]{64}=2](https://tex.z-dn.net/?f=b%3D%5Csqrt%5B6%5D%7B64%7D%3D2)
Hence, our function is:

Answer:
(0, 1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y + 5x = 1
5y - x = 5
<u>Step 2: Rewrite Systems</u>
y + 5x = 1
- Subtract 5x on both sides: y = 1 - 5x
<u>Step 3: Redefine Systems</u>
y = 1 - 5x
5y - x = 5
<u>Step 4: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitution in <em>y</em>: 5(1 - 5x) - x = 5
- Distribute 5: 5 - 25x - x = 5
- Combine like terms: 5 - 26x = 5
- Isolate <em>x</em> term: -26x = 0
- Isolate <em>x</em>: x = 0
<u>Step 5: Solve for </u><em><u>y</u></em>
- Define equation: 5y - x = 5
- Substitute in <em>x</em>: 5y - 0 = 5
- Subtract: 5y = 5
- Isolate <em>y</em>: y = 1
Answer:
111 points
Step-by-step explanation:
First, thing I like to do is to convert word problems into an eqaution or write down the important information. So, Math = 37 points and now the points are tripled because of where she placed the word. Also, tripled is implying that her base score for the word is 3 times the original value.
So, 
= 111 points.