- 6 = z + 3<br>solve each equation for the unknown variable

Priya bought these items at the grocery store. Find each unit price. A. 12 eggs for $3. How much is the cost per egg? B. 3 pound

Ratling [72]

Answer: A. Cost per egg = $4 .

B. Cost per pound = $ 2.5

C. Cost per roll = $ 0.5

D. Cost per apple = $0.35

Step-by-step explanation:

Formula: cost per item = (total cost) ÷ (number of items)

A. 12 eggs for $3.

Cost per egg = $ (12÷3) = $4

So, Cost per egg = $4 .

B. 3 pounds of peanuts for $7.50

Cost per pound of peanuts = $ (7.50 ÷ 3)= $ 2.5

So, Cost per pound = $ 2.5

C. 4 rolls of toilet paper for $2.

Cost per roll = $ (2 ÷4 ) = $ 0.5

So, Cost per roll = $ 0.5

D. 10 apples for $3.50.

Cost per apple = $ (3.50 ÷ 10)= $ 0.35

So, Cost per apple = $0.35

4 0

4 years ago

Regina, Phil, and Joseph each wrote expressions to represent their hourly earnings for an after-school job where h represents th

Vladimir79 [104]

Answer:

Disagree

On weeks when Joseph works extra 2/3 hours more than Phil, Phil and Joseph can earn the same amount of money

Step-by-step explanation:

The given expression for the hourly earnings of Regina, Phil and Joseph are as follows;

Regina: 6.50·h + 16

Phil: 3·(2.5·H + 5)

Joseph: 7.50·h + 10

The number of hours worked = h

The hourly earnings for Phil equated to the hourly earnings of Joseph gives;

3·(2.5·H + 5) = 7.50·h + 10

Simplifying we get;

3 × 2.5·h + 3 × 5 = 7.50·h + 10

7.5·h + 15 = 7.50·h + 10

Which gives

15 = 10 + 5 = 10 which is not correct.

Therefore, when both Phil and Joseph works the same number of hours, in the week, Phil will earn 5 units more Joseph

However, we have that, where Joseph works extra 5/7.5 or 2/3 hours more than Phil, every week, they will earn the same amount of money every week.

Therefore, it is possible for Phil and Joseph to earn the same amount of money when Joseph works extra 2/3 hours more than Phil which gives;

On weeks when Joseph works extra 2/3 hours more than Phil, Phil and Joseph can earn the same amount of money.

3 0

3 years ago

Using Unit Rates to compare Ratios continued

nasty-shy [4]

Answer:

Brandon

Step-by-step explanation:

GIVEN: Branden and Pete each play running back. Branden carries the ball $75$ times for $550$ yards, and Pete has $42$ carries for $380$ yards.

TO FIND: Who runs farther per carry.

SOLUTION:

Total yards traveled by Brandon $=550\text{yards}$

No. of times ball carried by Brandon $=75\text{ times}$

Average yards per carry for Brandon $=\frac{\text{total yards traveled}}{\text{number of times ball carried}}$

$=\frac{550}{75}$

$=\frac{22}{3}\text{ yards per carry}$

$=7.33\text{ yards per carry}$

Total yards traveled by Pete $=380\text{ yards}$

No. of times ball carried by Pete $=42\text{ times}$

Average yards per carry for Pete $=\frac{\text{total yards traveled}}{\text{number of times ball carried}}$

$=\frac{380}{42}$

≅ $9\text{ yards per carry}$

As the number of yards per carry is higher for Brandon , therefore he runs farther per carry.

4 0

3 years ago

Determine if the following scale factor would be an enlargement or reduction.<br> scale factor: 2.5

Sati [7]

Answer: Enlargement

Step-by-step explanation: If the number is larger than 1 it is an enlargement if it is smaller it is a reduction.

5 0

3 years ago

Read 2 more answers

I don't know what I did wrong. I tried it twice but it said it was wrong

Dafna1 [17]

Answer:

I used Desmos. Heres a picture of what its supposed to look like.

Step-by-step explanation:

5 0

2 years ago

- 6 = z + 3solve each equation for the unknown variable​

- 6 = z + 3solve each equation for the unknown variable