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Harman [31]
3 years ago
7

- 6 = z + 3solve each equation for the unknown variable​

Mathematics
1 answer:
Nataly [62]3 years ago
4 0
Solution: Z= -9

Reasoning: -6 - 3 = -9
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What is the fiftieth term in the sequence 5, 7, 9, 11, 13 …?
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The 15th term in the given A.P. sequence is a₁₅ = 33.

According to the statement

we have given that the A.P. Series with the a = 5 and the d is 2.

And we have to find the 15th term of the sequence.

So, for this purpose we know that the

An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.

And the formula is a

an = a + (n-1)d

After substitute the values in it the equation become

an = 5 + (15-1)2

a₁₅ = 5 + 28

Now the 15th term is a₁₅ = 33.

So, The 15th term in the given A.P. sequence is a₁₅ = 33.

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If a piece of cardboard is 6 in long and I line up a hundred and ten of them what would be the length of my row and feet
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The senior class want to play a practical joke on the principal, who was a former college basketball star. They want to fill his
steposvetlana [31]

The number of basketball that will fill up the entire office is <u>approximately 16,615.</u>

<em><u>Recall:</u></em>

Volume of a spherical shape = \frac{4}{3} \pi r^3

Volume of a rectangular prism = l \times w \times h

<em><u>Given:</u></em>

Diameter of basketball = 9.5 in.

Radius of the ball = 1/2 of 9.5 = 4.75 in.

Radius of the ball in ft = 0.4 ft (12 inches = 1 ft)

Dimension of the office (rectangular prism) = 20 ft by 18 ft by 12 ft

  • First, find the volume of the basketball:

Volume of ball = \frac{4}{3} \pi r^3 = \frac{4}{3} \times \pi \times 4.75^3\\

Volume of basketball = 448.92 $ in^3

  • Convert to ft^3

1728 $ in.^3 = 1 $ ft^3

<em>Therefore,</em>

  • Volume of basketball = \frac{448.92}{1728} = 0.26 $ ft^3

  • Find the volume of the office (rectangular prism):

Volume of the office = 20 \times 18 \times 12 = 4,320 $ ft^3

  • Number of basket ball that will fill the office = Volume of office / volume of basketball

  • <em>Thus:</em>

Number of basket ball that will fill the office = \frac{4,320}{0.26} = 16,615

Therefore, it will take approximately <u>16,615 balls</u><u> to fill up the entire office</u>.

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