Evaluate 8+6÷2+(2+10) help and work with answer please

Mathematics

2 answers:

Svetradugi [14.3K]4 years ago

3 0

Answer:

Step-by-step explanation:

P E M D A S

8+6÷2+(2+10)

8+6÷2+(12)

8+3+12

11+12

The final answer is 23.

adell [148]4 years ago

3 0

Answer: 23

Step-by-step explanation:

Since we have Pemdas, we can rewrite the thing like 8 + (6/2) + 12. Now we get 8 + 3 + 12 = 23

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The triangles in the figure are similar: ΔABC ∼ ΔDEF. Which of the following statements must be true? options: A) AB/DE=BC/EF=CA

VikaD [51]

Answer:

Answer A

Step-by-step explanation:

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4 years ago

Read 2 more answers

I really don’t understand this and just need an explanation of how to do it.

sertanlavr [38]

$\bf ~\hspace{12em}\left( \cfrac{2n}{-3n\cdot -2n^2} \right)^4
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\cfrac{2n}{-3n\cdot -2n^2}\implies \cfrac{1}{-3n}\cdot \cfrac{2n}{-2n^2}\implies \cfrac{1}{-3n}\cdot \cfrac{2n}{2n\cdot -n}\implies \cfrac{1}{-3n}\cdot \cfrac{2n}{2n}\cdot \cfrac{1}{-n}$

$\bf \cfrac{1}{-3n}\cdot \boxed{1}\cdot \cfrac{1}{-n}\implies \cfrac{1}{-3n\cdot -n}\implies \cfrac{1}{3n^2}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\left( \cfrac{2n}{-3n\cdot -2n^2} \right)^4\implies \left( \cfrac{1}{3n^2} \right)^4\implies \stackrel{\textit{distributing the exponent}}{\cfrac{1^4}{3^4n^{2\cdot 4}}}\implies \cfrac{1}{81n^8}$