It wants it to be in slope-intercept form.
y=mx+b
We have to first find the slope and plug it into point-slope form.
y-y1=m(x-x1)
Find the slope of the second line. (I did this one first on accident)
Rise/run= 3/1= 3 The slope is 3. Plug that in along with the point (0,3)
y-3=3(x-0)
y-3=3x
Add 3 to the other side.
y= 3x +3 <- <em>for the second line</em><em>
</em>
Now, the second.
rise/run= 1/2= .5 Use point (6,0)
y-0=.5(x-6)
y= .5x-3
y=.5x-3 <- for the first line
I hope this helps!
~kaiker
Answer:
0
Step-by-step explanation:
Answer:
Step-by-step explanation:
B:Convert the fractional part only then add it to the whole number.
C : 9 1/2,3π,92/5,91/10
B : √26,5.5,5.8,31/5
B: -7,20/3, 7.1 ,√51 , 6π
C: -π , -√5 , -3/2,-1.03
Answer:
I suppose you're trying to make a triangle of some sort on a plane! So, in this case, yes the three points would reside all on the same plane. Making all three of them collinear.
Answer:
96 ft²
Step-by-step explanation:
in a cube all sides are congruent so you take one measurement and multiply it by the number of sides, so you do 16 × 6 equals 96.
