v + m = 32 and v = 5 + 2m are the equations that are used to determine m, the number of stuffed animals Mariposa has
Number of stuffed animals Mariposa has is 9 and number of stuffed animals with Veronica is 23
<h3>
<u>Solution:</u></h3>
Let "v" be the number of stuffed animals with Veronica
Let "m" be the number of stuffed animals with Mariposa
Given that,
Together, they have 32 stuffed animals
Therefore,
v + m = 32 --------- eqn 1
Veronica has 5 more than double the number of stutted animals as her friend Mariposa
Therefore,
Number of stuffed animals with Veronica = 5 + 2(number of stuffed animals with Mariposa)
v = 5 + 2m ---------- eqn 2
Thus eqn 1 and eqn 2 can be used to determine m, the number of stuffed animals Mariposa has
Let us solve eqn 1 and eqn 2
Substitute eqn 2 in eqn 1
5 + 2m + m = 32
5 + 3m = 32
3m = 32 - 5
3m = 27
<h3>m = 9</h3>
Substitute m = 9 in eqn 2
v = 5 + 2(9)
v = 5 + 18
<h3>v = 23</h3>
Thus number of stuffed animals Mariposa has is 9 and number of stuffed animals with Veronica is 23
Decimal: 25.3333, but converted properly it is
.253333....(repeating) so to the nearest thousands it would be .253
Answer:
None of the above
Step-by-step explanation:
None of the answer choices are even triangles, let alone right triangles. The sum of the two smaller sides isn't larger than the bigger side on any of the triangles, which means that they cannot be closed.
Welcome to Brainly!
Binomial Theorem will follow this pattern:
The powers start at 3 and decrease down to 0 for the first term,
and start at 0 and increase to 3 for the other term.
(2x+4)^3 =

See how the power counts down on the (2x)
and counts up on the 4?
That's the pattern that our expansion must follow.
I left a little space in front of each term.
The coefficient in front of each term will come from the fourth row of Pascal's Triangle. The one that looks like this:
1 3 3 1
Those are the coefficients we want:

We can clean this up a little bit by getting rid of some of the junk. Anything to the 0th power is 1. So let's suppress all of our 1's because multiplying by 1 is not important.

Now apply exponent rule, distributing the power to both the 2 and the x where applicable.

Remember, multiplication is COMMUTATIVE, meaning we can multiply things in any order. So let's bring the numerical portion to the front of each term and multiply it all out.
