All categories

4 years ago

What are the measures of Arc J K and ∠KIJ?

Mathematics

2 answers:

expeople1 [14]4 years ago

7 0

Answer:

104 and 52

Step-by-step explanation:

just did the assignment on edgen

Anestetic [448]4 years ago

6 0

Answer:

Measure of JK = 104

Measure of ∠KIJ = 52

Step-by-step explanation:

You might be interested in

write in graphing form please! A parabola that opens down with no stretch factor that has a vertex of (-6,5)

wolverine [178]

If it has no stretch factor, then there will be no coefficient. Meaning this is a lot easier. So, we equation is

(x+6)^2 + 5

Hope this helps!
<span />

8 0

3 years ago

will give brainiest if answered will give brainiest if answered will give brainiest if answered will give brainiest if answered

Licemer1 [7]

Answer:

A=2(wl+hl+hw)=2·(8·12+4·12+4·8)=352

Step-by-step explanation:

brainliest?

4 0

3 years ago

Read 2 more answers

If the actor is to the audience’s right the actor is _______.

kati45 [8]

I think the answer is stage left because if you flip your view point, you'll get stage left.
Hopefully that helped! :)

7 0

3 years ago

A student solves the following equation and

Phoenix [80]

Answer:

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

Step-by-step explanation:

Considering the expression

$\frac{3}{a+2}-6\cdot \frac{a}{-4+a^2}=\frac{1}{a-2}$

$\frac{3}{a+2}-\frac{6a}{-4+a^2}=\frac{1}{a-2}$

$\mathrm{Find\:Least\:Common\:Multiplier\:of\:}a+2,\:-4+a^2,\:a-2:\quad \left(a+2\right)\left(a-2\right)$

$\mathrm{Multiply\:by\:LCM=}\left(a+2\right)\left(a-2\right)$

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right)-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right)=\frac{1}{a-2}\left(a+2\right)\left(a-2\right)$

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right):\quad 3\left(a-2\right)$

$-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right):\quad -6a$

$\frac{1}{a-2}\left(a+2\right)\left(a-2\right):\quad a+2$

so equation becomes

$3\left(a-2\right)-6a=a+2$

$-3a-6=a+2$

$-3a-6+6=a+2+6$

$-4a=8$

$\mathrm{Divide\:both\:sides\:by\:}-4$

$\frac{-4a}{-4}=\frac{8}{-4}$

$a=-2$

$\mathrm{Verify\:Solutions}$

$\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{3}{a+2}-6\frac{a}{-4+a^2}-\frac{1}{a-2}\mathrm{\:and\:compare\:to\:zero}$

$\mathrm{Solve\:}\:a+2=0:\quad a=-2$

$\mathrm{Solve\:}\:-4+a^2=0:\quad a=2,\:a=-2$

$\mathrm{Solve\:}\:a-2=0:\quad a=2$

So the following points are undefined

$a=-2,\:a=2$

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

4 0

3 years ago

Pedro's goal is to have more than $1200 in savings in the next 12 months. He already has $480 saved and wants to save the same a

Leno4ka [110]

The answer to ur problem is c $60

8 0

3 years ago

Read 2 more answers