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BigorU [14]
3 years ago
13

In a game you have 1/20 probability of winning $76 and a 19/20 probability of losing $9. What is your expected value?

Mathematics
1 answer:
oee [108]3 years ago
5 0

Answer:

1

Step-by-step explanation:

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The answer to 5+5 is 10
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Simplify the expression 2(10)+2(x-2)
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Answer:

16 + 2x

Step-by-step explanation:

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Solve by substitution or elimination;<br><br> x+2y=-1<br> x-y=5
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I would love to use substitution (It is simplier that way I guess)

solve your system of equations.

x+2y=−1;x−y=5

Solve x+2y=−1 for x:

x+2y+−2y=−1+−2y(Add -2y to both sides)

x=−2y−1

Substitute (−2y−1) for x in x−y=5:

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−2y−1−y=5

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−3y−1+1=5+1(Add 1 to both sides)

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Substitute (−2) for y in x=−2y−1:

x=−2y−1

x=(−2)(−2)−1

x=3(Simplify both sides of the equation)

So the answer is (x = 3 and y = -2)

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2 years ago
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The length of time for one individual to be served at a cafeteria is a random variable having an exponential distribution with a
Leya [2.2K]

Answer:

a) 0.25

b) 52.76% probability that a person waits for less than 3 minutes

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \lambda e^{-\lambda x}

In which \lambda = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

In this question:

m = 4

a. Find the value of λ.

\lambda = \frac{1}{m} = \frac{1}{4} = 0.25

b. What is the probability that a person waits for less than 3 minutes?

P(X \leq 3) = 1 - e^{-0.25*3} = 0.5276

52.76% probability that a person waits for less than 3 minutes

3 0
3 years ago
What is the answer to 5n²/2n³×5n³
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5n(n^2+n+7)-3n(n^2+2n) 

<span>5n^3+5n^2+35n-3n^3-6n^2 </span>

<span>2n^3-n^2+35n </span>

<span>n(2n^2-n+35)</span>
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