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BigorU [14]
3 years ago
13

In a game you have 1/20 probability of winning $76 and a 19/20 probability of losing $9. What is your expected value?

Mathematics
1 answer:
oee [108]3 years ago
5 0

Answer:

1

Step-by-step explanation:

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PLEASEEEEE HELPPPPPP ASAPPPPP
kenny6666 [7]
The Pythagorean Theorem is a^2 + b^2 = c^2
It’s usually used on triangles when two sides are given but one isn’t. C represents the hypotenuse while A and B are interchangeable. So solving for the hypotenuse would look like √a^2+ b^2= c but solving for a or be would look like √c^2-b^2 = a and √c^2-a^2= b.

So number wise √5^2+12^2 = 13
7 0
3 years ago
Riley is saving up to buy a new television. She needs a total of $1,054.04. Riley has saved $200.66 already and earns $77.58 per
Gnesinka [82]

Answer:

11

Step-by-step explanation:

1,054.04-200.66=853.38

853.38/77.58=11

5 0
3 years ago
Convert 142 base four to base ten
liraira [26]
142_4=1\times4^2+4\times4^1+2\times4^0=16+16+2=34_{10}
8 0
3 years ago
The pentagonal area is 20 cm square. Point A located in the pentagon and equidistant from all sides of the pentagon about 5 cm.
Maurinko [17]

Answer:

  about 8 cm

Step-by-step explanation:

The formula for the area of a regular polygon is ...

  A = 1/2Pa . . . . where P is the perimeter and "a" is the apothem, the distance from the center to a side

Filling in your numbers, we have ...

  20 cm^2 = (1/2)P(5 cm)

Dividing by the coefficient of P, we find ...

  2×(20 cm^2)/(5 cm) = P = 8 cm

The perimeter of the pentagon is about 8 cm.

_____

<em>Comment on the problem</em>

This calculation makes use of the area formula, as apparently intended. A regular pentagon with an apothem of about 5 cm will have an area of about 90.8 cm^2. The given geometry is impossible, as the pentagon is nearly 10 cm across. It cannot have a perimeter of only 8 cm.

5 0
3 years ago
Find two positive real numbers whose product is a maximum. the sum is 80
Eduardwww [97]
Let's say the numbers are "a" and "b"

thus \bf y=ab\qquad &#10;\begin{cases}&#10;a+b=80\\&#10;b=80-a&#10;\end{cases}\implies y=a(80-a)\implies y=80a-a^2\\\\&#10;-----------------------------\\\\&#10;\cfrac{dy}{da}=80-2a

set the derivative to 0, and check the critical points, there's only one anyway

and do a first-derivative test, to see if it's a maximum
4 0
3 years ago
Read 2 more answers
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