Hello there! Your answer would be '<em>the actual distance between the cities is 320 kilometers</em>'.
Okay, so to solve this, we can use unit rates. We know that for every one centimeter we have eighty kilometers. So, whatever we multiply the centimeter value by, we can multiply the kilometer value by the same number and get our answer.
So if the centimeter value is 4, multiply the kilometer value by 4.
80 x 4 = 320
This means that the cities are 320 kilometers apart, and you have your answer!
Hope this helps, and have a great day!
Answer:
The amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600
Step-by-step explanation:
Let x be the amount in the account at 12% interest
So, 6000-x is the amount in the second account at 7% interest
First account:
Second account : 
We are given that At the end of the first year he had earned $590 in interest.
So, 
So,the amount in the account at 12% interest is $3400
The amount in the second account at 7% interest =6000-x=6000-3400=2600
Hence the amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600
Answer:
-|b| < b
Step-by-step explanation:
-b where?
Answer:
To see how these fractions are equal, I divided the numerators by the denominators. For instance, you could have 4 over 5 (4/5) and divide 4 by 5 (4/5) to get 0.8. Now you'll do the same thing for the fractions given
24/45=0.533...
8/15=0.533...
48/90=0.533...
5/9=0.5556
As you can see, the only fraction that doesn't equal 0.53, or the outlier, is 5/9 or 0.5556
Step-by-step explanation:
Answer:
11
Step-by-step explanation:
The two equations appear to be ...
- 12x +4y = 152
- 32x +12y = 420
These can be solved for y using Cramer's rule:
y = (152(32) -420(12))/(4(32) -12(12)) = -176/-16 = 11
The cost of the vegetarian lunch is 11.
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<em>Comment on Cramer's Rule</em>
For equations ...
ax +by =c
dx +ey = f
The solutions are ...
x = (bf -ey)/(bd -ea)
y = (cd -fa)/(bd -ea) . . . . note the denominators are the same expression
Once you memorize the pattern of products, this can be the simplest way to solve a pair of equations--especially if you only need one of the variable values.
