Answer:
Genotypic ratio = 1 Bb: 1 bb
Phenotypic ratio = 1 black rabbit : 1 brown rabbit
Explanation:
This question involves a gene coding for hair color in rabbits. The allele for Black hair (B) is dominant to the allele for brown hair (b).
According to this question, a black rabbit whose mother is brown haired (bb) is crossed with a brown hair rabbit. This means that the black rabbit will have a genotype 'Bb' while the brown rabbit will have a genotype 'bb'. Each parent will produce the following gametes:
Bb - B and b
bb - b and b
Using these gametes in a punnet square (see attached image), the following proportion of offsprings will be produced:
Bb, Bb, bb and bb
This means that the;
Genotypic ratio = 1 Bb: 1 bb
Phenotypic ratio = 1 black rabbit : 1 brown rabbit
Answer:
44Kj
Explanation:
These are the equations for the reaction described in the question,
Vaporization which can be defined as transition of substance from liquid phase to vapor
H2(g)+ 1/2 O2(g) ------>H2O(g). Δ H
-241.8kj -------eqn(1)
H2(g)+ 1/2 O2(g) ------>H2O(l).
Δ H =285.8kj ---------eqn(2)
But from the second equation we can see that it moves from gas to liquid, we we rewrite the equation for vaporization of water as
H2O(l) ------>>H2O(g)---------------eqn(3)
But the equation from eqn(2) the eqn does go with vaporization so we can re- write as
H2O ------> H2(g)+ 1/2 O2(g)
Δ H= 285.8kj ---------------eqn(4)
To find Delta h of the vaporization of water at these conditions, we sum up eqn(1) and eqn(4)
Δ H=285.8kj +(-241.8kj)= 44kj
Hshehgecegsghebebususjsjieie
Answer:
A. 1km
Explanation:
The 1 km is equal to 1000 m.