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3 years ago

Match the following equation with the type of chemical reaction.

2 answers:

7 0

The general form of a synthesis reaction is A + B → AB
E)H2 + O2 ---> H2O synthesis

The general form of a decomposition reaction is AB → A + B
B)HBr ---> H2 + Br2

The general form of a single replacement is AB + C → AC + B
D)Al + H2SO4 ---> H2+ Al2(SO4)3

The general form of a double replacement is AB + CD → AD + CB
A)HCl + NaOH ---> H2O + NaCl

Combusion. usually involves oxygen and heat
C)C2H6 + O2 ---> H2O + CO2

Paha777 [63]3 years ago

6 0

A is is a double replacement reaction (Cations and anions switch)

B is a Decomposition reaction (Breaks down into simpler substances)

C is a Synthesis or Combination reaction (both are the same thing)

D is a Combustion reaction (compound made of carbon and hydrogen reacts with oxygen)

and E is a Single replacement reaction (Cations trade)

Hope this helps! :)

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The element nitrogen has an atomic weight of 14.0 and consists of two stable isotopes nitrogen-14 and nitrogen-15. The isotope n

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The mass of N-15 is 15 amu.

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What does it mean if a solution is a "weak acid "? Strong acid? Give logical ph values for each

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Answer:

A weak acid is an acid that partially dissociates into its ions in an aqueous solution or water. In contrast, a strong acid fully dissociates into its ions in water. At the same concentration, weak acids have a higher pH value than strong acids.

Explanation:

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3 years ago

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3 years ago

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What mass of aluminum is needed to produce 0.500 mole of aluminum chloride?

3241004551 [841]

Answer: " 13.5 g Al " ;

→ that is: "13.5 grams of aluminum."

____________________________

Explanation:

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Note: What is missing from the question is the "balanced chemical equation" for the "chemical reaction" that contains:

The reactants: "aluminum (Al) " ; and "chlorine (Cl) " ; and:

The product: "aluminum choloride (AlCl₃) " .

____________________________

The "balanced chemical equation" is:

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2 Al + 3 Cl₂ → 2 AlCl₃ ;

_____________________________

Note: The molecular weight of "aluminum (Al)" is: " 26.98 g /mol " .

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So: We call solve using a technique known as: "dimensional analysis" :

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0.500 mol AlCl₃ * $(\frac{2mol Al}{2mol AlCl_{3} }) * (\frac{26.98g Al}{1 mol Al}) = ?$

____________________________

Note: The units of "mol AlCl₃" cancel out to "1' ; and:

The units of "mol Al" cancel out to "1" ; and we are left with:

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" $\frac{(0.500 * 2 * 26.98)}{2}$ g Al ["grams of aluminum"] ;

____________________________

Note: We can "cancel out the "2's" ; since "2/2 = 1 " ; and we have:

→ (0.500 * 26.98) g Al ;

= 13.49 g Al ;

→ Round to 3 (Three) significant figures;

→ Since: "0.500" has 3 (Three) significant figures:

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= 13.5 g Al ; that is: "13.5 grams of aluminum."

____________________________

Hope this is helpful!

Best wishes to you in your academic pursuits—and within the "Brainly" community!

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