All categories

3 years ago

42.6 divided into 10 to the power of 2

Mathematics

2 answers:

aev [14]3 years ago

8 0

Answer:

The answer is 0.426

Step-by-step explanation:

10 to the power of 2 is 100 because 10 x 10= 100 when you divide a decimal by 100 just move the decimal point 2 times to the left

Paraphin [41]3 years ago

3 0

Answer:

0.426

Step-by-step explanation:

10 to the power of 2 is 100.

42.6 divided by 100 is 4.026, as you move the decimal places backwards by 2 times as there is 2 zeroes in 100.

You might be interested in

Calvin and Daniel are two mailmen. There are 94 mail pieces that have to be delivered. If Daniel delivered 43 pieces of mail, ho

Eva8 [605]

Answer:

Step-by-step explanation:

94-43

5 0

4 years ago

How to calculate angular velocity in radians per second.

weeeeeb [17]

Explanation:

You can calculate angular velocity in radians per second by using linear units.

That should be correct

5 0

2 years ago

N over 4 - 20 = -1 how do i solve this

Vera_Pavlovna [14]

n/4-20=-1

n/4=19 => Addition property of equality

n=4.75 or 4 3/4 => Division property of equality

6 0

3 years ago

(please hurry) Determine the slope of the line from the graph.<br><br> -1<br> 6<br> 2

umka21 [38]

-1 because m (slope) is going in a negative direction and for every x unit to the right, y is going 1 unit down

6 0

3 years ago

An isosceles trapezoid ABCD with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). What is the value of a, if p

horrorfan [7]

Answer:

a = -0.3575

Step-by-step explanation:

The points A and D lie on the x-axis, this means that they are the x-intercepts of the parabola, and therefore we can find their location.

The points A and B are located where

$y=a(x+1)(x-5)=0$

This gives

$x=-1$

$y=5$

Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e

$B_x=A_x+\frac{2}{tan(60)} =-1+\frac{2\sqrt{3} }{3}$