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Monica [59]
3 years ago
8

Write an exponential function in the form y=b^x that goes through the points (0,9) and (3,4608)

Mathematics
1 answer:
zhuklara [117]3 years ago
5 0

Answer:

y = 9 * bˣ

Step-by-step explanation:

y = a * bˣ

9 = a * b⁰ = a * 1

a = 9

4608 = 9 * b³

b³ = 512

b = 8

y = 9 * bˣ

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I ready 3 5/3 x (-8 1/3)=
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Answer:

-350/9 (improper fraction)

-38 8/9 (mixed number)

Step-by-step explanation:

Converting to improper fractions :

  1. 3 5/3
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  • 9/3 + 5/3
  • <u>14/3</u>

    2. -8 1/3

  • -(8 x 3/3 + 1/3)
  • -(24/3 + 1/3)
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Multiplying them :

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6 0
2 years ago
Read 2 more answers
What is the vertex form of y=2x^2-8x+1
bezimeni [28]

Answer:

2(x-2)^2-7

Step-by-step explanation:

y=2x^2-8x+1

When comparing to standard form of a parabola: ax^2+bx+c

  • a=2
  • b=-8
  • c=1

Vertex form of a parabola is: a(x-h)^2+k, which is what we are trying to convert this quadratic equation into.

To do so, we can start by finding "h" in the original vertex form of a parabola. This can be found by using: \frac{-b}{2a}.

Substitute in -8 for b and 2 for a.

\frac{-(-8)}{2(2)}

Simplify this fraction.

\frac{8}{4} \rightarrow2

\boxed{h=2}

The "h" value is 2. Now we can find the "k" value by substituting in 2 for x into the given quadratic equation.

y=2(2)^2-8(2)+1

Simplify.

y=-7

\boxed{k=-7}

We have the values of h and k for the original vertex form, so now we can plug these into the original vertex form. We already know a from the beginning (it is 2).

a(x-h)^2+k\\ \\ 2(x-2)^2-7

6 0
3 years ago
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Andreas93 [3]

Answer:

54

Step-by-step explanation:

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3 years ago
Solve for variable m.<br> m-n=5
podryga [215]

Answer:

m = 5 + n

Step-by-step explanation

Add n to both sides

m = 5+n

7 0
4 years ago
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