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vichka [17]
3 years ago
10

AJ is the bisector of ∠HJI. Determine the value of x. ANSWERS: A) 50 B) 10 C) 8 D) 25

Mathematics
1 answer:
Norma-Jean [14]3 years ago
3 0

Answer:

B) 10

Step-by-step explanation:

∠IJA= ∠HJA

ΔIJA has twice smaller side opposite ∠J than ∠A

Similarly

ΔHLA side 5 opposite  ∠J,

So x/5= 20/10 ⇒ x= 5*2= 10

Answer choice is B) 10

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2х - бу = 2<br>x + бу = 28​
scZoUnD [109]

Answer:

x = 10

y = 3

Step-by-step explanation:

Given

2x - 6y = 2

x + 6y = 28

Add both equations

2x + x -6y + 6y = 2 + 28

3x = 30

Divide both sides by 3

x = 30/3

x = 10

Substitute 10 for x in either equations to get y

Using equation 2 , we have

x + 6y = 28

10 + 6y = 28

Subtract 10 from both sides

10 - 10 + 6y = 28 - 10

6y = 18

Divide both sides by by 6

y = 18/6

y = 3

Therefore

x = 10

y = 3

7 0
3 years ago
Which is bigger 0.17 or 0.165
Bogdan [553]
0.17 is bigger because you compare the values of the number in each place. There is no whole number, the tenths place is equal. Then in the hundredths place you have a 6 and a 7. 6<7 so therefore 0.17> 0.165. To help yourself out u can add a 0 at the end to then more easily compare .170 to .165
5 0
3 years ago
How do you turn -0.2 into a fraction
Gemiola [76]

-2/10 which equates to -1/5

7 0
3 years ago
Read 2 more answers
X^2-2x−4=0 please leave ans in surd form and simplify​
Jobisdone [24]

Step-by-step explanation:

using the quadratic formula......

3 0
3 years ago
Read 2 more answers
BC =using the Distance Formula
riadik2000 [5.3K]

Answer: Option A: 5

Step-by-step explanation:

If yo have the pairs (a, b) and (c, d)

The distance between these two points is:

distance = √( (a - c)^2 + (b - d)^2)

Here we want to find the distance between points B and C.

We can see that the coordinates of each one are:

point B: (-5, 5)

Point C: (-1, 2)

Then the distance between these points is:

AB = √( (-5 -(-1))^2 + (5 -2)^2) = 5

AB = √( 4^2 + 3^2)

Then the correct option is A

5 0
3 years ago
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