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vichka [17]
3 years ago
10

AJ is the bisector of ∠HJI. Determine the value of x. ANSWERS: A) 50 B) 10 C) 8 D) 25

Mathematics
1 answer:
Norma-Jean [14]3 years ago
3 0

Answer:

B) 10

Step-by-step explanation:

∠IJA= ∠HJA

ΔIJA has twice smaller side opposite ∠J than ∠A

Similarly

ΔHLA side 5 opposite  ∠J,

So x/5= 20/10 ⇒ x= 5*2= 10

Answer choice is B) 10

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A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
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The sum of the given series can be found by simplification of the number

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Reasons:

The given sequence is presented as follows;

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  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

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\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

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\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

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