1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ycow [4]
3 years ago
8

A manufacturer estimates that the average worker can assemble products according to the function P(t)=8.47t+10t+6 where t ≥ 0 ,

t represents the number of weeks since the worker was hired, and P(t) represents the number of products the worker can assemble in an hour.
How many products can the average worker assemble per hour when he or she first starts working?
Mathematics
1 answer:
Snowcat [4.5K]3 years ago
3 0

Answer:

24

Step-by-step explanation:

We are given an equation that estimates how many products can an average worker assemble per hour. To obtain that value we have to insert <em>t, </em>which represents how many weeks the worker is employed. We are said that the worker just started working, so the number of weeks he is employed is 1, ie. <em>t </em>= 1. If we insert that into the equation we obtain:

P(1) = 8.47*1+10*1+6

      = 8.47+10+6

      = 24.47

Therefore, the worker produces 24.47 products per hour. We will round that number and then we get the answer that the worker produces 24 products per hour.

You might be interested in
I need explanation and answer please,thanks.
Alla [95]
What’s the question?
3 0
3 years ago
860÷43 what is the answer?​
Dvinal [7]

Answer:

20

Step-by-step explanation:

You would do this by dividing 43 into 860

7 0
3 years ago
Read 2 more answers
Members of the track team can run 400 min an average time of 64.6 seconds. The
vova2212 [387]

Answer:

T maximum=T average -7.8 seconds

T minimum=T average +7.8 seconds

Step-by-step explanation:

Calculation for the equation that can be

use to find the maximum and minimum times for the track team

Using this equation to find the maximum times for the track team

T maximum=T average -7.8 seconds

T maximum=64.6 seconds-7.8 seconds

Using this equation to find the minimum times for the the track team

T minimum=T average +7.8 seconds

T minimum=64.6 seconds +7.8 seconds

Therefore the equation for the maximum and minimum times for the track team are :

T maximum=T average -7.8 seconds

T minimum=T average +7.8 seconds

6 0
3 years ago
Find all the real cube roots of 1000/27 <br><br><br> 10/3 <br> 10/9 <br> -10/9 <br> -10/3
gulaghasi [49]
Can you do prime factoriztion

1000
100 * 10
10 * 10 * 10

27
9 * 3
3 * 3 * 3

cube root (1000/27) = 10/3
7 0
3 years ago
Read 2 more answers
All help is much appreciated please and thank you
scoundrel [369]
Anddd Similar traingles for one more time.

Here,
RQ/RP = RS/RT = QS/PT = 1/2


Using the values of QS and PT will give,

\frac{y}{y + 46}  =  \frac{1}{2} \\  \\  2y =y + 46 \\  \\  y = 46


Therefore y= 46 units.
6 0
3 years ago
Other questions:
  • What is the middle number of 8 and 15
    6·2 answers
  • Which expression demonstrates the use lf the commutative property of addition in the first step of simplifying the expression (-
    12·2 answers
  • Point D is on segment BC. Segment BC measures 8x
    13·1 answer
  • Evaluate the following expressions<br> 1)-8-(-4)=
    14·1 answer
  • (Please help, Very desperate and I have a limited amount of time to get this done please hurry asap)
    15·1 answer
  • According to the chart of holly complained to their mother That her stomach hurt and she could not breathe, which organism is t
    6·1 answer
  • May someone pls help me. i kinda really could use some help &lt;:}
    12·1 answer
  • Please help with the top question !
    9·2 answers
  • If 1 over 5 gallons of water fills 2 over 3 of an container, how much water will fill the whole container?
    13·1 answer
  • Rachel’s earrings are in the shape of a triangle. The height of the earrings is 1 1/2 inches and the base is 3/5 inches. What is
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!