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ycow [4]
3 years ago
8

A manufacturer estimates that the average worker can assemble products according to the function P(t)=8.47t+10t+6 where t ≥ 0 ,

t represents the number of weeks since the worker was hired, and P(t) represents the number of products the worker can assemble in an hour.
How many products can the average worker assemble per hour when he or she first starts working?
Mathematics
1 answer:
Snowcat [4.5K]3 years ago
3 0

Answer:

24

Step-by-step explanation:

We are given an equation that estimates how many products can an average worker assemble per hour. To obtain that value we have to insert <em>t, </em>which represents how many weeks the worker is employed. We are said that the worker just started working, so the number of weeks he is employed is 1, ie. <em>t </em>= 1. If we insert that into the equation we obtain:

P(1) = 8.47*1+10*1+6

      = 8.47+10+6

      = 24.47

Therefore, the worker produces 24.47 products per hour. We will round that number and then we get the answer that the worker produces 24 products per hour.

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For a criminal trial, 8 active and 4 alternate jurors are selected. Two of the alternate jurors are male and two are female. Dur
aleksley [76]

Answer:

The answer would be 1/6

6 0
2 years ago
Need Answer Fast Please to solve the Linear Expression: 5(5n+2)+(3-2n)
tatyana61 [14]

Answer:

23n +13

Step-by-step explanation:

5(5n+2)+(3-2n)

Distribute

25n + 10 +3 -2n

Combine like terms

25n -2n  + 10+3

23n +13

3 0
3 years ago
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Brad is installing a hot tub in his 30 ft by 20 ft back yard. The hot tub has a radius of 5 feet. If he randomly shoots
ddd [48]

Answer:

13% chance

Step-by-step explanation:

Area of backyard = length * width

A = 30 ft * 20 ft

A = 600 ft^{2}

Area of bathtub = π r^{2}

A = π * 5^{2}

A = 78.54 ft^{2}

Probability of arrow landing in tub can be found by dividing Area of the bathtub by the area of the backyard, and then multiplying by 100 for a percentage

Prob. = 78.54/600

Prob. = 0.13

Prob. = 0.13 * 100

Prob. = 13%

7 0
3 years ago
Find the arc length of the given curve between the specified points. x = y^4/16 + 1/2y^2 from (9/16), 1) to (9/8, 2).
lutik1710 [3]

Answer:

The arc length is \dfrac{21}{16}

Step-by-step explanation:

Given that,

The given curve between the specified points is

x=\dfrac{y^4}{16}+\dfrac{1}{2y^2}

The points from (\dfrac{9}{16},1) to (\dfrac{9}{8},2)

We need to calculate the value of \dfrac{dx}{dy}

Using given equation

x=\dfrac{y^4}{16}+\dfrac{1}{2y^2}

On differentiating w.r.to y

\dfrac{dx}{dy}=\dfrac{d}{dy}(\dfrac{y^2}{16}+\dfrac{1}{2y^2})

\dfrac{dx}{dy}=\dfrac{1}{16}\dfrac{d}{dy}(y^4)+\dfrac{1}{2}\dfrac{d}{dy}(y^{-2})

\dfrac{dx}{dy}=\dfrac{1}{16}(4y^{3})+\dfrac{1}{2}(-2y^{-3})

\dfrac{dx}{dy}=\dfrac{y^3}{4}-y^{-3}

We need to calculate the arc length

Using formula of arc length

L=\int_{a}^{b}{\sqrt{1+(\dfrac{dx}{dy})^2}dy}

Put the value into the formula

L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4}-y^{-3})^2}dy}

L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4})^2+(y^{-3})^2-2\times\dfrac{y^3}{4}\times y^{-3}}dy}

L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4})^2+(y^{-3})^2-\dfrac{1}{2}}dy}

L=\int_{1}^{2}{\sqrt{(\dfrac{y^3}{4})^2+(y^{-3})^2+\dfrac{1}{2}}dy}

L=\int_{1}^{2}{\sqrt{(\dfrac{y^3}{4}+y^{-3})^2}dy}

L= \int_{1}^{2}{(\dfrac{y^3}{4}+y^{-3})dy}

L=(\dfrac{y^{3+1}}{4\times4}+\dfrac{y^{-3+1}}{-3+1})_{1}^{2}

L=(\dfrac{y^4}{16}+\dfrac{y^{-2}}{-2})_{1}^{2}

Put the limits

L=(\dfrac{2^4}{16}+\dfrac{2^{-2}}{-2}-\dfrac{1^4}{16}-\dfrac{(1)^{-2}}{-2})

L=\dfrac{21}{16}

Hence, The arc length is \dfrac{21}{16}

6 0
2 years ago
the width of a rectangle is x centimetres and its length is (x+ 2) cm. Write down an expression for the perimeter of the rectang
yKpoI14uk [10]

Given:

The width of a rectangle is x centimeters and its length is (x+ 2) cm.

To find:

The expression for the perimeter of the rectangle.

Solution:

We know that, perimeter of a rectangle is

Perimeter=2(Length+Width)

We have,

Width = x cm

Length = (x+2) cm

Putting these values in the above formula, we get

Perimeter=2((x+2)+x)

Perimeter=2(2x+2)

Perimeter=2(2x)+2(2)

Perimeter=4x+4

Therefore, the required expression for the perimeter of the rectangle is (4x+4) cm.

6 0
2 years ago
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