Answer:
20
Step-by-step explanation:
You would do this by dividing 43 into 860
Answer:
T maximum=T average -7.8 seconds
T minimum=T average +7.8 seconds
Step-by-step explanation:
Calculation for the equation that can be
use to find the maximum and minimum times for the track team
Using this equation to find the maximum times for the track team
T maximum=T average -7.8 seconds
T maximum=64.6 seconds-7.8 seconds
Using this equation to find the minimum times for the the track team
T minimum=T average +7.8 seconds
T minimum=64.6 seconds +7.8 seconds
Therefore the equation for the maximum and minimum times for the track team are :
T maximum=T average -7.8 seconds
T minimum=T average +7.8 seconds
Can you do prime factoriztion
1000
100 * 10
10 * 10 * 10
27
9 * 3
3 * 3 * 3
cube root (1000/27) = 10/3
Anddd Similar traingles for one more time.
Here,
RQ/RP = RS/RT = QS/PT = 1/2
Using the values of QS and PT will give,

Therefore y= 46 units.