Answer:
usbqjqnamallqnbajabqjqnqkqlqlqllqqlqoqoqnajajhchhsgavbsujwhwjwjqqbq.
hshsjwhwjwjuwubwbwwuwhquuwqjqjqkqbqv pangit mo potang ina mo bulok wlang silbe wag kana mag ajabajajajqkqjbqiqiq
Step 1: Find the area of the bases (triangles)
A = 1/2 * base * height
A = 1/2 * 16 * 6
A = 48
48 + 48 = 96
Area of the triangles = 96 cm^2
Step 2: Find the area of the sides (rectangles)
A = base * height
A1 = 16 * 12
A1 = 192
A2 = 10 * 12
A2 = 120
120 + 120 = 240
240 + 192 = 432 cm^2
Step 2: Add the areas together
96 + 432
528 cm^2
Hope this helps!! :)
<span>D. 7/8
Hope it helped :)</span>
$1.80 if the question was ( he would have 3/5 of the amount he started with)
Answer:
35.25
Step-by-step explanation:
Give the data set:
23 37 49 34 35 41 40 26 32 22 38 42
We are expected to calculate the midquartile of the given data set.
22 23 26 32 34 35 37 38 40 41 42 49
First step is to find the lower quartile which comprises of
22 23 26 32 34 35
Here the Q1 is (26+32)/2 = 58/2= 29
Second step to find the upper quartile which comprises of
37 38 40 41 42 49
Here the Q3 is (40+41) /2 = 81/2 = 41.5
Then to find the midquartile which is (Q1+Q3) /2 where Q1 is 29 and Q3 is 41.5
= (29+41.5)/2
= (70.5) /2 = 35.25
