Answer:
4.05% probability that a randomly selected adult has an IQ greater than 123.4.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
Probability that a randomly selected adult has an IQ greater than 123.4.
This is 1 subtracted by the pvalue of Z when X = 123.4. So
has a pvalue of 0.9595
1 - 0.9595 = 0.0405
4.05% probability that a randomly selected adult has an IQ greater than 123.4.
Answer:
C
Step-by-step explanation:
The last reasoning is the side angle side theorem. In the whole proof, there is no mention of an angle. So the answer has to involve prooving that the angle in between the two sides that have been proven similar is the same in both traingles. This is best accomplished by statement C.
Answer:
1, 3, 4 i hope this helps ;)
Step-by-step explanation:
As the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1
As per the question statement, we are given a new mathematical operation a△b=a^2-b/b-a^2 and we are supposed to find the value of 4△3 using the same operation.
Given, a△b=a^2-b/b-a^2
now 4△3 = (4^2-3) / (3-4^2)
4△3 = (16-3) / (3-16)
4△3 = 13 / -13
4△3 = -1
Hence, as the new mathematical operation is defined by a△b=a^2-b/b-a^2, the value of 4△3 using the same operation will be 4△3 = -1.
- Mathematical operation: An operator in mathematics is often a mapping or function that transforms components of one space into elements of another.
To learn more about mathematical operation, click on the link given below:
brainly.com/question/8959976
#SPJ1
Answer:
<h3>73220±566.72</h3>
Step-by-step explanation:
The formula for calculating the confidence interval is expressed as;
CI = xbar ± z*s/√n
xbar is the sample mean = $73,220
z is the z score at 99% CI = 2.576
s is the standard deviation = $4400
n is the sample size = 400
Substitute the given values into the formula;
CI = 73,220 ± 2.576*4400/√400
CI = 73,220 ± 2.576*4400/20
CI = 73,220± (2.576*220)
CI = 73220±566.72
Hence a 99% confidence interval for μ is 73220±566.72
