Answer:
u-shaped; y-intercept (0,6); symmetrical with respect to the y-axis
Step-by-step explanation:
Given that y = 2x² + 6
The graph would be the shape of that of a parabola. It can be u shaped or n shaped depending on the value of the coefficient of a comparing with the standard equation y = ax² + bx + c. If a > 0, it is u shape and if a < 0, it is n shape.
For this question, since a > 0 it would be u shaped and the intercept can be gotten by putting x = 0.
Therefore y = 0² + 6 = 0
The intercept is at (0,6) and is symmetrical with respect to the y-axis
First list all the terms out.
e^ix = 1 + ix/1! + (ix)^2/2! + (ix)^3/3! ...
Then, we can expand them.
e^ix = 1 + ix/1! + i^2x^2/2! + i^3x^3/3!...
Then, we can use the rules of raising i to a power.
e^ix = 1 + ix - x^2/2! - ix^3/3!...
Then, we can sort all the real and imaginary terms.
e^ix = (1 - x^2/2!...) + i(x - x^3/3!...)
We can simplify this.
e^ix = cos x + i sin x
This is Euler's Formula.
What happens if we put in pi?
x = pi
e^i*pi = cos(pi) + i sin(pi)
cos(pi) = -1
i sin(pi) = 0
e^i*pi = -1 OR e^i*pi + 1 = 0
That is Euler's identity.
Answer:
there are no instructions
Step-by-step explanation:
pls fix ur question
