2 years ago

Write each expression using exponents

Mathematics

1 answer:

konstantin123 [22]2 years ago

6 0

Answer:

almost positive

Step-by-step explanation:

w^3(x^4 y)

3^3(a x b^4)

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Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that

kherson [118]

Answer:

The answer is

$f(x) = {\displaystyle 8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }$

Step-by-step explanation:

Remember that Taylor says that

$f(x) = {\displaystyle \sum\limits_{k=0}^{\infty} \frac{f^{(k)}(a) }{k!}(x-a)^k }$

For this case

$f^{(0)} (-2) = 8(-2)-3(-2)^3 = 8\\f^{(1)} (-2) = 8-3(3)(-2)^2 = -28\\f^{(2)} (-2) = -3(3)2(-2) = -36\\f^{(2)} (-2) = -3(3)2 = -18$

$f(x) = {\displaystyle 8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }$

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3 years ago

Given m||n, find the value of x.<br> t<br> m<br> (2X-24)<br> (x+5)

mamaluj [8]

hope this helps

May i have brainliest

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2 years ago

What is the x intercepts of the mid point f(x)=(x-2)(x-4)

BigorU [14]

F(x)= -2x+6 i think so

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3 years ago

Is my solution correct?

nlexa [21]

Hello there!

Yes, your solution is correct! A way to check it is replacing the value you found for x into x in the equation.

3(2-x) = 7 - 4x ⇒ 3(2-1) = 7 - 4(1)

And now solve 3(2-1) = 7 - 4(1).

3(1) = 7 - 4(1)

3 = 7 - 4

3 = 3

Since it is a true statement that 3 is equal to 3, it means your solution of x = 1 is correct. Good job! :)

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$\bf ~~~~~~\textit{parabola vertex form}
\\\\
\begin{array}{llll}
\boxed{y=a(x- h)^2+ k}\\\\
x=a(y- k)^2+ h
\end{array}
\qquad\qquad
vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\
-------------------------------\\\\
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3 years ago

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