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Katen [24]
2 years ago
12

Write each expression using exponents

Mathematics
1 answer:
konstantin123 [22]2 years ago
6 0

Answer:

almost positive

Step-by-step explanation:

w^3(x^4 y)

3^3(a x b^4)

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Nonamiya [84]
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4 0
3 years ago
Using the quadratic formula to solve 4x2 – 3x + 9 = 2x + 1, what are the values of x?
yaroslaw [1]

Answer:

The value of x is:

x=\dfrac{5\pm \sqrt{103}i}{8}

Step-by-step explanation:

we have to use the quadratic formula to solve for x.

The equation is given as:

4x^2-3x+9=2x+1

which could also be written as:

4x^2-3x+9-2x-1=0\\\\4x^2-3x-2x+9-1=0\\\\\\4x^2-5x+8=0

The quadratic formula for the quadratic equation of the type:

ax^2+bx+c=0 is given as:

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

Here we have:

a=4, b=-5 and c=8.

Hence, by the quadratic formula we have:

x=\dfrac{-(-5)\pm \sqrt{(-5)^2-4\times 8\times 4}}{2\times 4}\\\\x=\dfrac{5\pm \sqrt{25-128}}{8}\\\\\\x=\dfrac{5\pm \sqrt{103}i}{8}

Hence, the value of x is:

x=\dfrac{5\pm \sqrt{103}i}{8}

8 0
3 years ago
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Aleksandr-060686 [28]

Answer:

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MA_775_DIABLO [31]

From the diagram above you can see that points A and B have coordinates (8,0) and (-4,6), respectively.

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Then

y-0=\dfrac{6-0}{-4-8}(x-8),\\ \\y=-\dfrac{6}{12}(x-8),\\ \\y=-\dfrac{1}{2}(x-8),\\ \\y=-\dfrac{1}{2}x+4.

Answer: y=4-\dfrac{1}{2}x.

8 0
3 years ago
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An=3*(4^(n-1)) is the explicit
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