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2 years ago

To show that ADB = CBD by AAS, what must be the value of x?

Mathematics

1 answer:

Vadim26 [7]2 years ago

3 0

Answer:

x=13

Step-by-step explanation:

1)Set them equal to each other

6x-1=4x+25

2)Subtract 4x from both sides

2x-1=25

3)Add 1 to both sides

2x=26

4)Divide by 2

x=13

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klasskru [66]

$\bf |x^2+3x-1|\ \textless \ 3\implies 
\begin{cases}
+(x^2+3x-1)\ \textless \ 3\\\\
-(x^2+3x-1)\ \textless \ 3
\end{cases}\\\\
-------------------------------\\\\
x^2+3x-1\ \textless \ 3\implies x^2+3x-4\ \textless \ 0\implies (x+4)(x-1)\ \textless \ 0
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x\ \textless \ 
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1
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-(x^2+3x-1)\ \textless \ 3\implies x^2+3x-1\boxed{\ \textgreater \ }-3
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x^2+3+2\ \textgreater \ 0\implies (x+2)(x+1)\ \textgreater \ 0\implies x\ \textgreater \ 
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8 0

2 years ago

Will give brainliest 1. What is the formula for experimental probability? 2. What is a trial?

Mariulka [41]

Answer:

1) Formula for experimental probability:

Experimental Probability = $\frac{No.OfFavourableOutcomes}{No.OfPossibleOutcomes}$

2) Any performance or a random experiment is called a trial.

5 0

2 years ago

Find the value of r so the line that passes through (-5,2) and (3,r) has a slope of -1/2

soldier1979 [14.2K]

The value of r so the line that passes through (-5,2) and (3,r) has a slope of -1/2 is -2

Solution:

Given that line is passing through point (-5, 2) and (3, r)

Slope of the line is $\frac{-1}{2}$

Need to determine value of r.

Slope of a line passing through point $\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right)$ is given by following formula:

$\text { Slope } m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ --- eqn 1

$\text { In our case } x_{1}=-5, y_{1}=2, x_{2}=3, y_{2}=\mathrm{r} \text { and } m=-\frac{1}{2}$

On substituting the given value in (1) we get

$\begin{array}{l}{-\frac{1}{2}=\frac{r-2}{3-(-5)}} \\\\ {\text { Solving the above expression to get value of } r} \\\\ {=>-\frac{1}{2}=\frac{r-2}{3+5}} \\\\ {=>-8=\frac{r-2}{3+5}} \\\\ {=>-8=2(r-2)} \\\\ {=>-8=2 r-4} \\\\ {=>2 r=-8+4} \\\\ {=>2 r=-4} \\\\ {=>r=\frac{-4}{2}=-2}\end{array}$

Hence the value of "r" is -2

8 0

3 years ago

Graphs of what functions are shown below?

shtirl [24]

Answer:

-3/5

Step-by-step explanation:

6 0

3 years ago

I need help with #5 please

Alika [10]

Distance from a point to a line (Coordinate Geometry)

Method 1: When the line is vertical or horizontal , the distance from a point to a vertical or horizontal line can be found by the simple difference of coordinates . Finding the distance from a point to a line is easy if the line is vertical or horizontal. We simply find the difference between the appropriate coordinates of the point and the line. In fact, for vertical lines, this is the only way to do it, since the other methods require the slope of the line, which is undefined for evrtical lines.

Method 2: (If you're looking for an equation) Distance = | Px - Lx |

Hope this helps!

4 0

2 years ago