A and B are n×n matrices. Check the true statements below: A. (detA)(detB)=detAB. B. The determinant of A is the product of the
1 answer:
Answer with Step-by-step explanation:
We are given that
A and B are matrix.
A.We know that for two square matrix A and B
Then,
Therefore, it is true.
B. det A is the product of diagonal entries in A.
It is not true for all matrix.It is true for upper triangular matrix.
Hence, it is false.
C.
When is a factor of the characteristics polynomial of A then -5 is an eigenvalue of A not 5.
Hence, it is false.
D.An elementary row operation on A does not change the determinant.
It is true because when an elementary operation applied then the value of matrix A does not change.
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Answer:
h = - 105
Step-by-step explanation:
Given
= - 7.5 ( multiply both sides by 14 to clear the fraction )
h = - 105
Answer:
The receiver must be placed at a distance of 6.125 ft from the center.
Step-by-step explanation:
The dish is of parabola shape with the length of 14 feet and 2 feet deep from the center.
A parabola is a curve which is a set of all points in the plane which are at equal distance away from a given point called focus and given line called directrix.
We have to find out the point at which all the waves comes to one point where the receiver must be placed is the focus of the parabola.
The above scenario is shown in the image which can be converted in mathematical graphical representation of the parabolic curve.
The extreme two end points becomes, (-7,2) and (7,2)
The general equation for such parabola is:
x² = 4ay
where, a is the distance from the center and the focus.
Since, (7,2) satisfy the equation so,
7² = 4a×2
a = 49 /8
Thus,
<u>The receiver must be placed at a distance of 6.125 ft from the center.</u>
The length of the KN is 4.4
Step-by-step explanation:
We know from Pythagoras theorem
In a right angle ΔLMN
Base² + perpendicular² = hypotenuse ²
From the properties of triangle we also know that altitudes are ⊥ on the sides they fall.
Hence ∠LKM = ∠NKM = 90 °
Given values-
LM=12
LK=10
Let KN be “s”
⇒LN= LK + KN
⇒LN= 10+x eq 1
Coming to the Δ LKM
⇒LK²+MK²= LM²
⇒MK²= 12²-10²
⇒MK²= 44 eq 2
Now in Δ MKN
⇒MK²+ KN²= MN²
⇒44+s²= MN² eq 3
In Δ LMN
⇒LM²+MN²= LN²
Using the values of MN² and LN² from the previous equations
⇒12² + 44+s²= (10+s) ²
⇒144+44+s²= 100+s²+20s
⇒188+s²= 100+s²+20s cancelling the common term “s²”
⇒20s= 188-100
∴ s= 4.4
Hence the value of KN is 4.4
