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Oksanka [162]
3 years ago
10

Please help picture shown !!!!!!

Mathematics
1 answer:
Triss [41]3 years ago
4 0
D)a Because the square root and square cancel

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Suppose a manufacturer sells a product as $2 per unit. If q units are sold, (a) write the total revenue function, (b) and find t
Ahat [919]

Answer:

We are given that  a manufacturer sells a product as $2 per unit.

Quantity = q units

So, Total revenue = \text{Cost per unit} \times quantity

Total revenue = 2q

So, the total revenue function is  2q

Marginal revenue is the derivative of the revenue functions

So, Marginal revenue = \frac{dR}{dq} =2

The marginal revenue function is 2

The constant marginal revenue function mean that the revenue earned by the addition of the output is constant.

7 0
3 years ago
If can babysits 2 hours and she earns $14 then she works 4 hours and gets $28 what how much does she make if she does 6 hours
mr Goodwill [35]

Answer:

He will earn 42$

Step-by-step explanation:

7 0
3 years ago
Solve the following equation q=1/3bh , for b
xz_007 [3.2K]

b=3q/8 or at least thats what I got

7 0
3 years ago
Assume z = x + iy, then find a complex number z satisfying the given equation. d. 2z8 – 2z4 + 1 = 0
kodGreya [7K]

Answer: complex equations has n number of solutions, been n the equation degree. In this case:

Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i11,25°}

Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i101,25°}

Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i191,25°}

Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i281,25°}

Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i78,75°}

Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i168,75°}

Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i258,75°}

Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i348,75°}

Step-by-step explanation:

I start with a variable substitution:

Z^{4} = X

Then:

2X^{2}-2X+1=0

Solving the quadratic equation:

X_{1} =\frac{2+\sqrt{4-4*2*1} }{2*2} \\X_{2} =\frac{2-\sqrt{4-4*2*1} }{2*2}

X=\left \{ {{0,5+0,5i} \atop {0,5-0,5i}} \right.

Replacing for the original variable:

Z=\sqrt[4]{0,5+0,5i}

or Z=\sqrt[4]{0,5-0,5i}

Remembering that complex numbers can be written as:

Z=a+ib=|Z|e^{ic}

Using this:

Z=\left \{ {{{\frac{\sqrt{2}}{2} e^{i45°} } \atop {{\frac{\sqrt{2}}{2} e^{i-45°} }} \right.

Solving for the modulus and the angle:

Z=\left \{ {{\sqrt[4]{\frac{\sqrt{2}}{2} e^{i45}} = \sqrt[4]{\frac{\sqrt{2}}{2} } \sqrt[4]{e^{i45}} } \atop {\sqrt[4]{\frac{\sqrt{2}}{2} e^{i-45}} = \sqrt[4]{\frac{\sqrt{2}}{2} } \sqrt[4]{e^{i-45}} }} \right.

The possible angle respond to:

RAng_{12...n} =\frac{Ang +360*(i-1)}{n}

Been "RAng" the resultant angle, "Ang" the original angle, "n" the degree of the root and "i" a value between 1 and "n"

In this case n=4 with 2 different angles: Ang = 45º and Ang = 315º

Obtaining 8 different angles, therefore 8 different solutions.

3 0
3 years ago
If y = 5x – 4, which of the following sets represents possible inputs and outputs of the function, represented as ordered pairs?
lidiya [134]

Answer:

B

Step-by-step explanation:

Substitute the x value into the right side of the function and if the value obtained is equal to the y value of the point then it is a solution.

(0, - 4) → y = 5(0) - 4 = 0 - 4 = -4 ← True

(2, 6) → y = 5(2) - 4 = 10 - 4 = 6 ← True

(4, 20) → 5(4) - 4 = 20 - 4 = 16 ← False

(4, 16) → 5(4) - 4 = 20 - 4 = 16 ← True

(0, - 4), (2, 6), (4, 16) ← possible inputs and outputs

8 0
3 years ago
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