Question

A square fits exactly inside a circle with each of the vertices being on the circumference of the circle. The square has sides length of X cm. The area of the circle is 56cm^2. Work out the value of x. Give your answer correct to 3sf

Answer 1

Answer: The value of x is 5.970.

Step-by-step explanation:

Given: The square has sides length of X cm.

Let r be the radius of the circle.

The square fits exactly inside a circle with each of the vertices being on the circumference of the circle.

Then diagonal of square = diameter of circle

i.e. $\sqrt{2}x= 2r$    [Diagonal of square = $\sqrt{2}$(side)]

i.e. $r=\dfrac{x}{\sqrt{2}}$

area of circle =$\pi r^2$

i.e. $56=\frac{22}{7}(\frac{x}{\sqrt{2}})^2$

$56=\frac{22}{7}\times\frac{x^2}{2}\\\\\Rightarrow\ x^2= \dfrac{7}{11}\times56\\\\\Rightarrow\ x^2=35.636\\\\\Rightarrow\ x=\sqrt{35.636}\approx5.970$

Hence, the value of x is 5.970.