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3 years ago

7

Can u write an expression that equals 40.Including an exponet.... please help me☺☺☺

2 answers:

Vlad1618 [11]3 years ago

5 0

7(exponent 2) - 3(exponent 2)
Which equals 49-9=40

vagabundo [1.1K]3 years ago

4 0

(2^2) +36
could work

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(3-4i)(6i+7)-(2-3i)

Sergeu [11.5K]

Answer:

43-7i

Step-by-step explanation:

We are given the expression:

$\displaystyle \large{(3 - 4i)(6i + 7) - (2 - 3i)}$

First, expand 3-4i in 6i+7. To expand binomial with binomial, first we expand 3 in 6i+7 then expand -4i in 6i+7.

$\displaystyle \large{[(3 \cdot 6i) + (3 \cdot 7) + ( - 4i \cdot 6i) + ( - 4i \cdot 7)]- (2 - 3i)} \\ \displaystyle \large{[18i + 21 - 24 {i}^{2} - 28i]- (2 - 3i)}$

Now combine like terms.

$\displaystyle \large{[ - 10i+ 21 - 24 {i}^{2} ]- (2 - 3i)}$

<u>I</u><u>m</u><u>a</u><u>g</u><u>i</u><u>n</u><u>a</u><u>r</u><u>y</u><u> </u><u>U</u><u>n</u><u>i</u><u>t</u>

$\displaystyle \large{i = \sqrt{ - 1} } \\ \displaystyle \large{ {i}^{2} = - 1 }$

Therefore:-

$\displaystyle \large{[ - 10i+ 21 - 24 ( - 1) ]- (2 - 3i)} \\ \displaystyle \large{[ - 10i+ 21 + 24]- (2 - 3i)} \\ \displaystyle \large{[ - 10i+ 45]- (2 - 3i)}$

Then expand negative sign in 2-3i; remember that negative times negative is positive and negative times positive is negative.

$\displaystyle \large{- 10i+ 45 - (2 - 3i)} \\ \displaystyle \large{- 10i+ 45 - 2 + 3i}$

Combine like terms.

$\displaystyle \large{43 - 7i}$

5 0

2 years ago

Is false about most standard savings accounts?

cluponka [151]

You can build a small fortune or provide for a comfortable retirement with investment in standard savings accounts. . . . . . . . . . NOT !

8 0

3 years ago

Simplify the expression below.<br> 5x² (3x + 2)

Westkost [7]

Step-by-step explanation:

$5x^2(3x+2)$

Distribute into 5x² into (3x +2).

$15x^3+10x^2$

The simplified expression is <em>15x³ + 10x²</em>

3 0

3 years ago

Read 2 more answers

Click once to choose an answer. Click again to change your answer. Choose all that locate the ordered pair in the correct quadra

forsale [732]

Answer:

$Quadrant\ IV = (5, -3)$

$Quadrant\ I = (9, 11)$

$Quadrant\ II = (-1, 3)$

$Quadrant\ III = (-2, -4)$

Step-by-step explanation:

Given

$Quadrant\ IV = (5, -3)$

$Quadrant\ II = (-4, -8)$

$Quadrant\ I = (9, 11)$

$Quadrant\ II = (-1, 3)$

$Quadrant\ III = (-2, -4)$

Required

Determine which coordinate fall in the right quadrant

First, we split the each quadrant into x and y axis

In the first:

x and y is +

In the second:

x is - and y is +

In the third

x and y are -

In the fourth

x is + and y is -

Comparing the given coordinates to their respective quadrants, base on the conditions stated above

$Quadrant\ IV = (5, -3)$ is correct

$Quadrant\ I = (9, 11)$ is correct

$Quadrant\ II = (-1, 3)$ is correct

$Quadrant\ III = (-2, -4)$ is correct

$Quadrant\ II = (-4, -8)$ is incorrect

3 0

3 years ago

I need answers quick !!!!!

Rainbow [258]

This point is not a solution to those lines.

8 0

3 years ago

Read 2 more answers