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Anna [14]
3 years ago
7

Can u write an expression that equals 40.Including an exponet.... please help me☺☺☺

Mathematics
2 answers:
Vlad1618 [11]3 years ago
5 0
7(exponent 2) - 3(exponent 2)
Which equals 49-9=40
vagabundo [1.1K]3 years ago
4 0
(2^2) +36
could work
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(3-4i)(6i+7)-(2-3i)
Sergeu [11.5K]

Answer:

43-7i

Step-by-step explanation:

We are given the expression:

\displaystyle \large{(3 - 4i)(6i + 7) - (2 - 3i)}

First, expand 3-4i in 6i+7. To expand binomial with binomial, first we expand 3 in 6i+7 then expand -4i in 6i+7.

\displaystyle \large{[(3 \cdot 6i) + (3 \cdot 7) + ( - 4i \cdot 6i) + ( - 4i \cdot 7)]- (2 - 3i)}  \\  \displaystyle \large{[18i + 21  - 24 {i}^{2}  - 28i]- (2 - 3i)}

Now combine like terms.

\displaystyle \large{[ - 10i+ 21  - 24 {i}^{2} ]- (2 - 3i)}

<u>I</u><u>m</u><u>a</u><u>g</u><u>i</u><u>n</u><u>a</u><u>r</u><u>y</u><u> </u><u>U</u><u>n</u><u>i</u><u>t</u>

\displaystyle \large{i =   \sqrt{ - 1} } \\ \displaystyle \large{ {i}^{2}  =   - 1 }

Therefore:-

\displaystyle \large{[ - 10i+ 21  - 24  ( - 1) ]- (2 - 3i)}  \\   \displaystyle \large{[ - 10i+ 21   + 24]- (2 - 3i)}  \\   \displaystyle \large{[ - 10i+ 45]- (2 - 3i)}

Then expand negative sign in 2-3i; remember that negative times negative is positive and negative times positive is negative.

\displaystyle \large{- 10i+ 45 -  (2 - 3i)}  \\   \displaystyle \large{- 10i+ 45 -  2 + 3i}

Combine like terms.

\displaystyle \large{43 - 7i}

5 0
2 years ago
Is false about most standard savings accounts?
cluponka [151]
You can build a small fortune or provide for a comfortable retirement with investment in standard savings accounts. . . . . . . . . . NOT !
8 0
3 years ago
Simplify the expression below.<br> 5x² (3x + 2)
Westkost [7]

Step-by-step explanation:

5x^2(3x+2)

Distribute into 5x² into (3x +2).

15x^3+10x^2

The simplified expression is <em>15x³ + 10x²</em>

3 0
3 years ago
Read 2 more answers
Click once to choose an answer. Click again to change your answer. Choose all that locate the ordered pair in the correct quadra
forsale [732]

Answer:

Quadrant\ IV = (5, -3)

Quadrant\ I = (9, 11)

Quadrant\ II = (-1, 3)

Quadrant\ III = (-2, -4)

Step-by-step explanation:

Given

Quadrant\ IV = (5, -3)

Quadrant\ II  = (-4, -8)

Quadrant\ I = (9, 11)

Quadrant\ II = (-1, 3)

Quadrant\ III = (-2, -4)

Required

Determine which coordinate fall in the right quadrant

First, we split the each quadrant into x and y axis

In the first:

x and y is +

In the second:

x is - and y is +

In the third

x and y are -

In the fourth

x is + and y is -

Comparing the given coordinates to their respective quadrants, base on the conditions stated above

Quadrant\ IV = (5, -3)  is correct

Quadrant\ I = (9, 11) is correct

Quadrant\ II = (-1, 3) is correct

Quadrant\ III = (-2, -4) is correct

Quadrant\ II  = (-4, -8) is incorrect

3 0
3 years ago
I need answers quick !!!!!
Rainbow [258]
This point is not a solution to those lines. 
8 0
3 years ago
Read 2 more answers
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