All categories

3 years ago

4x+3x-5x-5+5x+5x-x3+x2-8x+2x+7-5x

Mathematics

1 answer:

Yuri [45]3 years ago

5 0

1.) Group like terms: 4x+3x-5x+5x+5x-3x+2x-8x+2x-5x-5+7

2.) Add similar elements: = 4x+3x-5x+5x+5x-3x+2x-8x+2x-5x=0

3.) =-5+7

4.) Add/Subtract the numbers: -5 + 7 = 2

Your Answer: 2

You might be interested in

A 110 point final exam is

statuscvo [17]

Answer:

There are 45 2-point questions and 5 4-point questions

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A student is using a spinner with four equal sections numbered 1 through 4. He also tosses a fair coin. What is the correct samp

nignag [31]

Answer:

C. {(1,H), (2,H), (3,H), (4,H), (1,T), (2,T), (3,T), (4,T)}

8 0

3 years ago

Read 2 more answers

What is the answer 3 x −4=−8

Artyom0805 [142]

Step-by-step explanation:

3x-4=-8

3x=-8+4

3x=-4

x=-(4/3)

8 0

3 years ago

Two right triangles are shown. First, find the missing leg of the triangle on the right. Then you have two lengths to use to fin

jasenka [17]

Answer:

x = 30m

Step-by-step explanation:

GIVEN :-

There are 2 right-angled triangles.

In the triangle on the right side ,

Hypotenuse = 26m
Base = 10m

In the triangle on the left side ,

Base = 18m

TO FIND :-

Length of the common perpendicular to both triangles.
Length of the hypotenuse of the triangle on the left side.

FACTS TO KNOW BEFORE SOLVING :-

$Hypotenuse = \sqrt{Base^2 + Perpendicular^2}$ .
$Perpendicular = \sqrt{Hypotenuse^2 - Base^2}$

SOLUTION :-

In the triangle on the right side ,

$Perpendicular = \sqrt{26^2 - 10^2} = \sqrt{676 - 100} = \sqrt{576} = 24m$

⇒ Perpendicular of the triangle on right side = Perpendicular of the triangle on left side.

In the triangle on the left side ,

$Hypotenuse = \sqrt{24^2 + 18^2} = \sqrt{576 + 324} = \sqrt{900} = 30m$

∴ x = 30m

3 0

3 years ago

Use the graph of y =g(x) to graph the given function.

Semenov [28]

Answer:

See image attached

Step-by-step explanation:

This type of transformation corresponds to a reflection of the function's graph around the x axis. Therefore one should obtain the mirror image of the segments on he upper quadrant as shown in red in the attached image.

3 0

3 years ago