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3 years ago

Someone please help

Mathematics

1 answer:

taurus [48]3 years ago

7 0

Answer:

K' (6,-4)

L' (0,-7)

M' (6,-10)

N' (8,-7)

Step-by-step explanation:

As we are rotating 180 degrees, We just need to change the sign of each of the points.

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How would you describe the correlation in the data? Explain your reasoning. (2 points).

ANTONII [103]

Answer:

Step-by-step What is a linear function in the form y= mx + b for the line passing through (4.5, -4.25) with y-intercept 2.5 yup help pleade

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3 years ago

Write an equation of the line that passes through (1,2) and is parallel to the line y = -5x +4

STatiana [176]

Answer:

y=-5x+7

Step-by-step explanation:

Prallel lines have the same slope

so the slope of the unknown line is -5

and passes through(1,2)

y-2=-5(x-1)

slope-intercept form:y=-5x+7

6 0

3 years ago

Reading proficiency: An educator wants to construct a 99.5% confidence interval for the proportion of elementary school children

Shkiper50 [21]

Answer:

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error of the interval is given by:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In this problem, we have that:

$p = 0.69$

99.5% confidence level

So $\alpha = 0.005$ , z is the value of Z that has a pvalue of $1 - \frac{0.005}{2} = 0.9975$ , so $Z = 2.81$ .

Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?

This is n when M = 0.07. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.07 = 2.81\sqrt{\frac{0.69*0.31}{n}}$

$0.07\sqrt{n} = 1.2996$

$\sqrt{n} = \frac{1.2996}{0.07}$

$\sqrt{n} = 18.5658$

$(\sqrt{n})^{2} = (18.5658)^{2}$

$n = 345$

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

4 0

3 years ago

Cally

photoshop1234 [79]

Answer:

$10.08+4.99x\leq 50$

$x\leq 8$

The maximum pounds of cheese that Ariana can buy is 8

Step-by-step explanation:

Let

x ---> the amount of cheese In pounds, that Ariana can buy

we know that

The cost of 3 loaves of bread plus the cost of the cheese must be less than or equal to $50

The inequality that represent this situation is

$3(3.36)+4.99x\leq 50$

$10.08+4.99x\leq 50$

solve for x

subtract 10.08 both sides

$4.99x\leq 50-10.08$

$4.99x\leq 39.92$

divide by 4.99 both sides

$x\leq 8$

Therefore

The maximum pounds of cheese that Ariana can buy is 8

3 0

3 years ago

Can you please help me solve this

Lerok [7]

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6 0

3 years ago

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